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3 years ago

Determine a planet from our solar system is located far from the sun. Describe the size and composition of this planet

Chemistry

2 answers:

amid [387]3 years ago

8 0

Jupiter is a very large planet mainly made up of hydrogen

Nataliya [291]3 years ago

6 0

Answer:

We could say that it is the planet Neptune

Explanation:

Neptune a gaseous planet. It is the planet furthest from the Sun being at an approximate distance of 4,500 million kilometers, its mass is 1,0241 x 10^26 kg. Neptune is composed of ice and rock, with a heavy and solid core similar to Earth's. It does not have a solid surface. It is a dense planet and its magnetic field is 27 times stronger than Earth's. Neptune has an atmosphere of 74% hydrogen, 25% helium and 1% methane.

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Klio2033 [76]

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3 years ago

Which particle of the atom has a negative charge?

Sophie [7]

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3 years ago

Read 2 more answers

Answer these two questions, please.

IRINA_888 [86]

Answer:

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3 years ago

Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn

mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$

Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with $E_{red}^{0}$ value lower than 1.51 V will donate electron to $Mn^{3+}$ and thus reduces $Mn^{3+}$ to $Mn^{2+}$ .

So, Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$ .

Metal with $E_{red}^{0}$ value lower than -0.40 V will donate electron to $Cr^{3+}$ and thus reduces $Cr^{3+}$ to $Cr$ .

So, Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$ .

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3 years ago

What tool measures mass?

Tatiana [17]

Answer:

balances and scales, measurement transducers, vibrating tube sensors, Newtonian mass measurement devices and the use of gravitational interaction between objects.

Explanation:

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3 years ago