The mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
<h3>What are iron ores?</h3>
Iron ores refers to minerals in which iron occur in combined form found in the earth's crust.
Some ores of iron include:
- hematite,
- magnetite,
- limonite, and
- siderite.
Molar mass of hematite, Fe₂O₃ = 160 g/mol
Molar mass iron = 56 g/mol
Percent mass of iron in hematite = 56/160 = 35%
The mass of hematite that contains 8.0×10³ kg of iron = 8.0 × 10³kg/0.35 = 2.29 × 10⁴ kg.
Therefore, the mass of hematite that contains 8.0×10³ kg of iron is 2.29 × 10⁴ kg.
Learn more about iron ores at: brainly.com/question/4693242
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Ka x Kb = Kw Kw = 1 x 10⁻¹⁴
(1.3 x 10⁻⁷) x Kb = 1 x 10⁻¹⁴
Kb = ( 1 x 10⁻¹⁴ ) / ( 1.3 x 10⁻⁷)
Kb = 7.7 x 10⁻⁸
Answer D
hope this helps!
Answer:- The hydroxide ion concentration of the solution is 
.
Solution:- The formula used to calculate pOH from hydroxide ion is:
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
When pOH is given and we are asked to calculate hydroxide ion concentration then we multiply both sides by negative sign and take antilog and what we get on doing this is:
![[OH^-]=10^-^p^O^H](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E-%5Ep%5EO%5EH)
pOH is given as 5.71 and we are asked to calculate hydrogen ion concentration. Let's plug in the given value in the formula:
![[OH^-]=10^-^5^.^7^1](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E-%5E5%5E.%5E7%5E1)
![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D)
= 0.00000195 or
So, the hydroxide ion concentration of the solution is .
Answer:
![[NH_2NO_2]=0.0868M](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.0868M)
Explanation:
Hello,
In this case, for the given chemical reaction, the first-order rate law is:
![r=\frac{d[NH_2NO_2]}{dt} =-k[NH_2NO_2]](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%5BNH_2NO_2%5D%7D%7Bdt%7D%20%3D-k%5BNH_2NO_2%5D)
Which integrated is:
![[NH_2NO_2]=[NH_2NO_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D%5BNH_2NO_2%5D_0exp%28-kt%29)
Thus, the concentration after 31642.0 s for a 0.384-M solution is:
![[NH_2NO_2]=0.384M*exp(-4.70x10^{-5}s^{-1}*31642.0s)\\](https://tex.z-dn.net/?f=%5BNH_2NO_2%5D%3D0.384M%2Aexp%28-4.70x10%5E%7B-5%7Ds%5E%7B-1%7D%2A31642.0s%29%5C%5C)
Best regards.
The answer is Na < Cl
Chlorine is more electronegative than sodium because this follows the trend of the periodic table. The trend states that an element's electronegativity increases from left to right of a period and bottom to up of a group. Since sodium and chlorine are from the same period, and chlorine is at the right of sodium, chlorine is more electronegative.
