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True [87]
3 years ago
13

A frame is marked down by 22 percent from an original price of $14.50. What is the new price? $3.19 $11.31 $13.72 $14.28 PLS HEL

P FAST IM BEING TIMED
Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0
Answer: 11:31

Explanation: 22 percent of 14.50 is 3.19, and because it is being marked down you subtract 3.19 from 14.50 to get this answer.
pychu [463]3 years ago
5 0

Answer:hi the answer is 11.31

Step-by-step explanation:

all you have to do is find what 22% of 14.50 and of course the answer is 11.31

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9 + 4 = 13 which is not an even number

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What is the value of p?<br><br> A) 55<br><br> B) 45<br><br> C) 35<br><br> D) 125
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The _____ function is the most basic function in a family of functions.
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Read 2 more answers
A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of
Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that \mu = 15.4, \sigma = 3.5

16 items are chosen at random

This means that n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16.8 - 15.4}{0.875}

Z = 1.6

Z = 1.6 has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

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3 years ago
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