Answer: 10:55
Step-by-step explanation:
Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.
The time the buses will be back at the depot simultaneously will be when:
N(a) * 25mins = N(b) * 35mins
Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.
Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc
Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc
This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.
So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is
at 08:00 + 2:55 = 10:55
Answer:
where are the tables i need a photo?
Step-by-step explanation:
Answer:
Step-by-step explanation:
The total number of students is 350 + 50 + 225 + 375 = 1000.
There are 225 students in band only, as well as 50 students in both band and choir. So there are 275 students in band out of the total of 1000, or 27.5%.
There are 350 students in choir only, as well as 50 students in both choir and band. So there are 400 students in choir, 50 of whom are also in band. So the probability is 50/400, or 12.5%.
The probabilities are not the same.
Since the probabilities are not the same, the probability of being in band is affected by whether or not the student is in choir. So the events are not independent.
<h3>
Answer: Solution is x = -2</h3>
You have two equations with y1 = f(x) and y2 = g(x).
We're looking for the values of x such that f(x) = g(x). This is the same as trying to solve y1 = y2.
The first row of the table shows y1 and y2 having the same value 5. So we just record the x value that goes with these y values.
Answer:
1. 3*8*10=240
2.6*6*12=432
Step-by-step explanation:
Hope that helps
Use l*w*h
