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Softa [21]
3 years ago
11

The ratio of the area to the circumference is A. 2r B.r/2 C. 2/r

Mathematics
2 answers:
weqwewe [10]3 years ago
4 0
It's nothing because e=mc^2
alexgriva [62]3 years ago
3 0
E=mc^2 ...............................................
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What is the area of △JKL in square units? KJL is a triangle. The angle J is 94 degree and the angle L is 26 degree. Side JK is 2
Tamiku [17]

Answer:

426.07 square units

Step-by-step explanation:

Recall that for a triangle whose angles are A,B,C  with corresponding sides a, b, c, the area G of the triangle may be computed as

G = 1/2 ab Sin C

or

G = 1/2 bc Sin A

or

G = 1/2 ac Sin B

Going by this, recall that the sum of angles in a triangle is 180 hence

94 + 26 + K = 180

120 + K = 180

Subtract 120 from both sides

K = 180 - 120

K = 60 degrees

Given that JK = 24 and JL = 41

G = 1/2 * 24 * 41 Sin 60

= 426.07 square units

8 0
3 years ago
10 + 3x < 4 or 2x + 5 > 11 in interval notation​
Stella [2.4K]

Answer:

( − ∞ , ∞ ) hope i help

Step-by-step explanation:

First, solve each inequality. I'll solve the first one first.

7 ≥ 2 x − 5

12 ≥ 2 x

6 ≥ x

Therefore, x could be any number less than or equal to 6. In interval notation, this looks like:

( − ∞ , 6 ]

The parenthesis means that the lower end is not a solution, but every number above it is. (In this case, the lower end is infinity, so a parenthesis must be used, since infinity is not a real number and so it cannot be a solution.) The bracket means that the upper end is a solution. In this case, it indicates that not only could  

x

be any number less than 6, but it could also be 6.

Let's try the second example:

3 x − 2 4 > 4

3 x − 2 > 16    3 x > 18 x > 6

Therefore, x could be any number greater than 6, but x couldn't be 6, since that would make the two sides of the inequality equal. In interval notation, this looks like:

( 6 , ∞ )  

The parentheses mean that neither end of this range is included in the solution set. In this case, it indicates that neither 6 nor infinity are solutions, but every number in between 6 and infinity is a solution (that is, every real number greater than 6 is a solution).

Now, the problem used the word "OR", meaning that either of these equations could be true. That means that either  x  is on the interval  ( − ∞ , 6 ] or the interval  ( 6 , ∞ )

. In other words,  x

is either less than or equal to 6, or it is greater than 6. When you combine these two statements, it becomes clear that  

x

could be any real number, since no matter what number  

x

is, it will fall in one of these intervals. The interval "all real numbers" is written like this:

( − ∞ , ∞ )

6 0
3 years ago
If AACD ~ AABE, find the value of x.
Anastaziya [24]

9514 1404 393

Answer:

  x = 16

Step-by-step explanation:

Corresponding sides are proportional.

  BE/CD = AE/AD

  20/(3x+8) = (x-1)/(x-1+27)

  20(x+26) = (3x+8)(x -1)

In standard form, this is ...

  3x^2 -15x -528 = 0

  x^2 -5x -176 = 0 . . . . . . divide by 3

  (x -16)(x +11) = 0 . . . . . . . factor

  x = 16

__

This is the positive value that makes the product zero. x=-11 will also make the product 0, but gives negative segment lengths in the geometry. It is an extraneous solution.

4 0
3 years ago
Please please answer these two (16-17) questions
valkas [14]
This would be C and B
3 0
3 years ago
Distributive Property (a+8)(a-3)=
polet [3.4K]

Distribute.

(a + 8)(a -3)

FOIL:

First, Outside, Inside, and Last

a * a = a^2

a * 3 = 3a

8 * a = 8a

8 * -3 = - 24

a^2 + 11a - 24

Distributed Expression: a^2 + 11a - 24

3 0
3 years ago
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