So in calculating this one its is really hard to explain how i get it on solve it but you must consider this factors that i give in getting the answer. First is the distance cover by the ball when it is hit by the club, Second is you must estimate both of those data when it is in the moon and in the earth whre the gravity of the earth is 9.8m/s^2 so by calculating the Gravity of the moon or gMoon is equal 1.74m/s^2
As per the question the wavelength of the microwave is given as 3.52 mm.
we are asked to calculate the frequency of the wave.
we know that microwave is a electromagnetic wave.
As per Clark Maxwell's electromagnetic theory ,every electromagnetic wave moves with a velocity equal to the velocity of light in vacuum and that is equal to 3×10^8 m/s.
From the equation of the wave,we know that velocity of wave is the product of frequency and wavelength.
Mathematically wave velocity
where f is the frequency of the wave and
is the wavelength.
As per the question 

Here 
Hence frequency of the wave 


Here Hertz [Hz] is the unit of frequency.
In a distance time graph, when the x and y values are positive (in first quadrant), the runner is moving forward.
While, if the distance value ( in the y axis) is negative, the runner is moving backwards ( towards the start) .
Hope it helps :)
Answer:
The maximum emf induced in the ring
= (2.882 × 10⁻⁷) V
Explanation:
According to the law of electromagnetic induction, the emf induced in the ring is given by
E = N BA w sin wt
The maximum emf induced is
E = N BA w
B = 30.5 μT = (30.5 × 10⁻⁶) T
A = (πD²/4)
D = 1.75 cm = 0.0175 m
A = (π×0.0175²/4) = 0.000240625 m²
Nw = 2π × 6.25 = 39.29 rad/s
E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29
E = (2.882 × 10⁻⁷) V
Hope this Helps!!!