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8090 [49]
3 years ago
13

The force vector A has components Ax = 5 N, Ay = -3 N. The force vector B has

Physics
1 answer:
jeka943 years ago
5 0

Answer:

In the picture.

Explanation:

I hope that it's a clear solution.

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What acceleration will a 1000-kg car experience if a force of 500 N is applied?
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Name the instrument that can be used to measure specific heat capacity​
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Read 2 more answers
An astronaut goes out for a space-walk at a distance above the earth equal to the radius of the earth. What is her acceleration
Lera25 [3.4K]

Answer:\frac{g}{4}

Explanation:

Let m be the mass of Astronaut

M=mass of earth

G=Gravitational constant

R=radius of Earth

Force Exerted by Earth on Astronaut

F=\frac{GmM}{R^2}

acceleration due to gravity is =\frac{F}{m}=g

g=\frac{GM}{R^2}

When it is at r=2R

g'=\frac{GM}{(2R)^2}

g'=\frac{GM}{4R^2}=\frac{g}{4}  

7 0
3 years ago
A. What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound f
nasty-shy [4]

Answer:

A)828.8Hz

B)869.2Hz

Explanation:

Here is a complete question;

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren? Speed of sound is 345m/s

b. What frequency does she receive after the ambulance has passed?

Vs= speed of the ambulance

, We convert to m/s for unit consistency

= 115 km/h= 115km× 1000m/1m × 1hr/3600s= 31.94m/s

Dopler effect is when observed frequency of wave changes with respect to the source or when observed moves relative to transmitting medium can be expressed as

f'=[ (v + vo)/(v- vs)]*f

=[ (v )/(v- vs)]*f

The sign vo and vs depends on vthe direction of the velocity

f= frequency of ambulance siren= 753Hz

v= speed of sound in air= 345m/s

Vo= speed of observer= 0

A) we are to determine the f' of ambulance as heard by person as ambulance approaching.

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v- vs)]*f

=[ (345)/(345-31.94)]×753

= 828.8Hz

B)What frequency does she receive after the ambulance has passed?

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v + vs)]*f

=[ (345)/(345 + 31.94)]×753

= 869.2Hz

=

4 0
3 years ago
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