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3 years ago

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The force vector A has components Ax = 5 N, Ay = -3 N. The force vector B has

1 answer:

jeka943 years ago

5 0

Answer:

In the picture.

Explanation:

I hope that it's a clear solution.

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"Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the defini

DaniilM [7]

I believe this is gravitational force

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3 years ago

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A skater extends her arms, holding a 2 kg mass in each hand. She is rotating about a vertical axis at a given rate. She brings h

Usimov [2.4K]

Explanation:

It is known that relation between torque and angular acceleration is as follows.

$\tau = I \times \alpha$

and, I = $\sum mr^{2}$

So, $I_{1} = 2 kg \times (1 m)^{2} + 2 kg \times (1 m)^{2}$

= 4 $kg m^{2}$

$\tau_{1} = 4 kg m^{2} \times \alpha_{1}$

$\tau_{2} = I_{2} \alpha_{2}$

So, $I_{2} = 2 kg \times (0.5 m)^{2} + 2 kg \times (0.5 m)^{2}$

= 1 $kg m^{2}$

as $\tau_{2} = I_{2} \alpha_{2}$

= $1 kg m^{2} \times \alpha_{2}$

Hence, $\tau_{1} = \tau_{2}$

$4 \alpha_{1} = \alpha_{2}$

$\alpha_{1} = \frac{1}{4} \alpha_{2}$

Thus, we can conclude that the new rotation is $\frac{1}{4}$ times that of the first rotation rate.

8 0

3 years ago

A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer

dlinn [17]

<h2>Answer:7.14 $ms^{-1}$ ,4.125 $ms^{-1}$ </h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let $v$ be the total velocity.

Given that, $v=8.25ms^{-1}$

We call the horizontal velocity as $v_{h}$ and the vertical velocity as $v_{v}$ .

$v_{h}$ = $vCos\alpha$

$v_{v}=vSin\alpha$

where $\alpha$ is the angle between the object and horizontal.

It is given that $\alpha =30^{0}$

$v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}$

$v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}$

7 0

3 years ago

To store stacks of clean plates, a cafeteria uses a closed cart with a spring-loaded shelf inside. Customers can take plates off

ruslelena [56]

The answer for the following problem is mentioned below.

The option for the question is "A" approximately.

<u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>

Explanation:

Given:

Spring constant (k) = 240 N/m

amount of the compression (x) = 0.40 m

To calculate:

Elastic potential energy (E)

We know;

<em>According to the formula;</em>

E = $\frac{1}{2}$ × k × x × x

<u>E = </u> $\frac{1}{2}$ <u> × k ×(x)²</u>

where;

E represents the elastic potential energy

K represents the spring constant

x represents amount of the compression in the string

So therefore,

Substituting the values in the above formula;

E = $\frac{1}{2}$ × 240 × (0.40)²

E = $\frac{1}{2}$ × 240 × 0.16

E = $\frac{1}{2}$ × 38.4

E = 19.2 J or approximately 20 J

<u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>

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3 years ago

0.0135 kg of steam at 100°C is

lora16 [44]

Answer:

33333.35 kg

Explanation:

I got it right on Acellus, rounded to 33300 sigfigs

8 0

2 years ago