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Ivenika [448]
3 years ago
8

The images output from your new color laser printer seem to be a little too blue. What can you do to fix this?

Physics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

The images output from your new color laser printer seem to be a little too blue. to fix this problem we need to calibrate the printer.

Explanation:

This can be done by opening the toolbox, clicking in the device setting folder their you get print quality page click on it. Under the print quality option click on the calibrate next to calibrate now. Then click OK unless when the 'your request has been sent to the device' appears on the screen. When the calibration ends again try printing. calibrating is useful for managing the proper alignment of the inkjet cartridge nozzle to the paper and each other, without proper calibration the print quality deteriorates.

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True or false ionic compounds that dissolve in water conduct electricity because they break into gases that move freely
Virty [35]
False....................................
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3 years ago
How does cells and tissues work together with the brain to do its job
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Cells are grouped together to carry out specific functions. A group of cells that work together form a tissue. Your body has four main types of tissues, as do the bodies of other animals. These tissues make up all structures and contents of your body.
4 0
2 years ago
The acceleration of a particle as it moves along a straight line is given by a (2t 1) m/s2, where t is in seconds. Suppose that
Cerrena [4.2K]

Answer:

 v = 158 m / s

Explanation:

In this kinematic problem they give us the acceleration of the body, the position and speed of the initial moment, let's use the definition of acceleration

       a = dv / dt

        dv = a dt

We integrate

        ∫ d v = ∫ (2t + 1) dt

        v = 2 (2t²) + 1t

We evaluate between the initial time t = 0 that has speed (vo) 8 m/s and the final time t with speed v

        v -8 = 4t2 + t

We already have the velocity formula as a function of time, let's calculate for t = 6 s

         v = 8 + 4 6² +6

         

         v = 158 m / s

3 0
4 years ago
A student standing in a canyon yells "echo", and her voice produces a sound wave of frequency of f = 0.61 kHz. The echo takes t
klasskru [66]

Answer:

d=627.9\ m  is the distance from the obstacle of reflection.

wavelength \lamb=0.5279\ m

Explanation:

Given that:

  • frequency of sound, f=610\ Hz
  • time taken for the echo to be heard, t=3.9\ s
  • speed of sound, v=322\ m.s^{-1}

We know,

\rm distance = speed \times time

<em>During an echo the sound travels the same distance back and forth.</em>

2d=v.t

2d=322\times 3.9

d=627.9\ m  is the distance from the obstacle of reflection.

<u>Now the wavelength of sound waves:</u>

\lambda=\frac{v}{f}

\lambda=\frac{322}{610}

\lamb=0.5279\ m

3 0
3 years ago
The areas of the pistons are 20 cm^2 and 100 cm^2. A force of 10 N is applied to the small piston. How much force is on the larg
strojnjashka [21]

Answer:

50N

Explanation:

A1 (area of the smaller piston) = 20cm² = 0.2m²

F1 (force acting on the smaller piston) = 10N

F2 (force acting on the larger piston) =?

A2 (area of the larger piston) = 100cm² = 1m²

F1 / A1 = F2 / A2

F2 = (F1*A2) / A1

F2 = (10*1) / 0.2

F2 = 50N

3 0
4 years ago
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