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Zigmanuir [339]
2 years ago
8

A machine has mechanical advantages 2, what does it means. plzz tell me the ans

Physics
1 answer:
Vlad [161]2 years ago
3 0

Answer:

Mechanical advantage is the measure of the force amplification achieved by using a tool , mechanical device or machine . ... So MA = 2 means that for example if you apply 100 N then your machine will multiply that force and generate 200 N..

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

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M
Zigmanuir [339]

Answer:

it’s 2.5 m/s

Explanation:

i’m too lazy but trust

6 0
3 years ago
A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump
GuDViN [60]

Answer:

The force is  F  =  1397 lb

Explanation:

From the question we are told that

    The length of the box is  l  =  19 \ in

    The width of the box is  w =  5 \ in

     The height is  h  =  4\ in

The pressure experience on one of the sides is mathematically represented as

     p = \frac{F}{A}

Where A is the area of the box which is mathematically evaluated as

    A =  l * w

substituting values

     A =  5 *19

      A = 95 \ in^2

This pressure is equivalent to the atmospheric pressure which has a constant value of  p = 14.7 pi

This implies that

        14.7  = \frac{F}{95}

=>   F  =  14.7 *95

=>    F  =  1397 lb

       

5 0
3 years ago
Is 45 m/s2 a scalar or a vector quantity and how do you know?
Umnica [9.8K]

Answer:

Explanation:

it is a vector as it has a magnitude and a direction. If it was a scalar quantity it would just have a magnitude and would be 45 m. Acceleration is an example of a vector quantity

5 0
3 years ago
Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this
maw [93]

Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

I = \frac{\epsilon_{max}}{R}

I = \frac{NBA\omega}{R}

Where

I= current

N = Number of loops

\omega = angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}

I = 578A

8 0
4 years ago
g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr
Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

a = \frac{GM}{r^2}

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

\frac{da}{dr} = -2\frac{GM}{r^3}

da = -2\frac{GM}{r^3}dr

At the same time since Newton's second law we know that:

F_w = ma

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

F_W = m (\frac{GM}{r^2} ) = 600N

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

dF_W = mda

dF_W = m(-2\frac{GM}{r^3}dr)

dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})

dF_W = -2F_W(\frac{dr}{r})

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})

dF_W = -0.3N

Therefore there is a weight loss of 0.3N every kilometer.

4 0
3 years ago
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