Answer:
solution:
to find the speed of a jogger use the following relation:
V
=
d
x
/d
t
=
7.5
×m
i
/
h
r
...........................(
1
)
in Above equation in x and t. Separating the variables and integrating,
∫
d
x
/7.5
×=
∫
d
t
+
C
or
−
4.7619
=
t
+
C
Here C =constant of integration.
x
=
0 at t
=
0
, we get: C
=
−
4.7619
now we have the relation to find the position and time for the jogger as:
−
4.7619 =
t
−
4.7619
.
.
.
.
.
.
.
.
.
(
2
)
Here
x is measured in miles and t in hours.
(a) To find the distance the jogger has run in 1 hr, we set t=1 in equation (2),
to get:
= −
4.7619
=
1
−
4.7619
= −
3.7619
or x
=
7.15
m
i
l
e
s
(b) To find the jogger's acceleration in m
i
l
/
differentiate
equation (1) with respect to time.
we have to eliminate x from the equation (1) using equation (2).
Eliminating x we get:
v
=
7.5×
Now differentiating above equation w.r.t time we get:
a
=
d
v/
d
t
=
−
0.675
/
At
t
=
0
the joggers acceleration is :
a
=
−
0.675
m
i
l
/
=
−
4.34
×
f
t
/
(c) required time for the jogger to run 6 miles is obtained by setting
x
=
6 in equation (2). We get:
−
4.7619
(
1
−
(
0.04
×
6 )
)^
7
/
10=
t
−
4.7619
or
t
=
0.832
h
r
s
We know, s = ut + 1/2gt²
In free-fall, u = 0
so, t = √2s/g
Now, substitute the values,
t = √2*4 / 9.8 [ -ve sign shows opposite direction only ]
t = √8/ 9.8
t = 0.90 sec
In short, Your Answer would be 0.90 sec
Hope this helps!
The Supernova will be observed on Earth 60,000 years from now.
<h3>
What is Supernova?</h3>
- A supernova is a star's tremendous and brilliant explosion. It is referred to as a supernova or a supernovae and is abbreviated as SN or SNe.
- This fleeting astronomical occurrence takes place either when a white dwarf is set off into uncontrolled nuclear fusion or during the latter phases of the development of a big star. The original object, known as the progenitor, either disintegrates completely or falls into a neutron star or black hole.
- Before fading over the course of several weeks or months, the peak optical luminosity of a supernova can be similar to that of an entire galaxy.
- Compared to novae, supernovae are more energetic. Nova, which in Latin means "new," refers to what appears to be a transitory new bright star in astronomy. Supernovae can be distinguished from regular novae by the prefix "super-."
To learn more about Supernova with the given link
brainly.com/question/12702138
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In Newtonian physics, the acceleration of a body is inversely proportional to mass. In Newtonian rotational physics, angular acceleration is inversely proportional to the moment of inertia of a frame.
The moment of Inertia is frequently given the image I. it's miles the rotational analog of mass. The moment of inertia of an object is a measure of its resistance to angular acceleration. because of its rotational inertia, you want torque to change the angular pace of an object. If there may be no net torque acting on an object, its angular speed will no longer change.
In linear momentum, the momentum p is the same as the mass m instances of the velocity v; whereas for angular momentum, the angular momentum L is the same as the instant of inertia I times the angular pace ω.
Learn more about angular acceleration here:-brainly.com/question/21278452
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Explanation:
First find the displacement in the x direction:
dₓ = 449 cos 66° + 1112 cos 169° + 1571 cos 26°
dₓ = 182.6 − 1091.6 + 1412
dₓ = 503 km
Next, find the displacement in the y direction:
dᵧ = 449 sin 66° + 1112 sin 169° + 1571 sin 26°
dᵧ = 410.2 + 212.2 + 688.7
dᵧ = 1311 km
The magnitude is:
d² = dₓ² + dᵧ²
d² = (503)² + (1311)²
d = 1404 km
The angle is:
tan θ = dᵧ / dₓ
tan θ = 1311 / 503
tan θ = 2.61
θ = 69°
1404 km and 69° north of east from New Orleans is approximately Toledo.
