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LenaWriter [7]
3 years ago
9

In lab you find that a 1-kg rock suspended above water weighs 10 N. When the rock is suspended beneath the surface of the water,

the scale reads 8 N.
a. What is the buoyant force on the rock?
b. If the container of water weighs 10 N on the weighing scale, what is the scale reading when the rock is suspended beneath the surface of the water?
c. What is the scale reading when the rock is released and rests at the bottom of the container?
a) 2 N
b) 12 N
c) 20 N
Physics
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

a. 2N

b. 12N

c. 20N

Explanation:

Dtaa given,

Weight of rock in air=10N

weight of rock in water =8N

a. When the rock is suspend in water, it will displace some water from thr container since Buoyant force is the acts upward and equals in magnitude to the volume of water displays,

The buoyant force is calculated as 10N-8N=2N

b. The scale reading will be the sum of the buoyant force and the weight of the container

scale reading =10N+2N=12N

c. When the rock rest at the bottom of the container, the weight of the rock(10N) is acting downward and the weight of the container also is acting downward. Hence the sum of the two weight gives the reading on the scale

scale reading=10N+10N=20N

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What is the reversal experienced by an image formed in a plane mirror called?
Lerok [7]

Answer:

Lateral inversion

Explanation:

When an object is placed in front of a plane mirror, the appearance of the object on the plane mirror appears as a reversal of the object. This effect is known as lateral inversion.

Lateral inversion occurs as a result of the fact that light is reflected by a plane mirror. The image formed by the plane mirror is as far behind the mirror as the object is in front of it. Hence lateral inversion occurs because of the way our brains perceive images on a plane mirror. The mirror image of symmetrical letters and objects do not show lateral inversion.

4 0
4 years ago
Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h
Dvinal [7]

Answer:

734.16 kg m/s^{2}

Explanation:

The problem is asking for the Force of pushing off the ground.

  • The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

             <em>Acceleration</em>: 12 m/s^{2}

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: \frac{1 kg}{9.80665 N} x \frac{x}{600 N} = \frac{600}{9.80665} = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/s^{2}

F = 734.16 kg m/s^{2}

7 0
3 years ago
If a **** was infinitely long could it rap around jo mama?
Alex777 [14]

Answer:

no it could not.

Explanation:

3 0
3 years ago
draw a labelled ray diagram to locate the image of an object formed by a convex lens of focal length 20cm when the object is pla
azamat
<h3><u>Answer</u> :</h3>

<u>Focal length of convex lens is taken positive.</u>

:\implies\sf\:\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

:\implies\sf\:\dfrac{1}{v}-\dfrac{1}{(-30)}=\dfrac{1}{20}

:\implies\sf\:\dfrac{1}{v}=\dfrac{1}{20}-\dfrac{1}{30}

:\implies\sf\:\dfrac{1}{v}=\dfrac{3-2}{60}

:\implies\:\boxed{\bf{\gray{v=60\:cm}}}

7 0
3 years ago
A shaving or makeup mirror is designed to magnify your face by a factor of 1.40 when your face is placed 20.0cm in front of it
Dennis_Churaev [7]

Answer:

(a) convex mirror

(b) virtual and magnified

(c) 23.3 cm

Explanation:

The having mirror is convex mirror.

distance of object, u = - 20 cm

magnification, m = 1.4

(a) As the image is magnified and virtual , so the mirror is convex in nature.

(b) The image is virtual and magnified.

(c) Let the distance of image is v.

Use the formula of magnification.

m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm

Use the mirror equation, let the focal length is f.

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm

Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm

5 0
3 years ago
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