Answer:
Pressure will decrease according to the Charles Gay Lussac law.
Explanation:
When there is a gas in a tank, and the moles of gas are not modified, neither the volume, we can notice that pressure will be modifying, in order to the absolute temperature, as directly proportion.
T° increase → Pressure increase
T° decrease → Pressure decrease
If the pressure keeps on constant, it will be the volume that would be modified according to the absolute T°, as a directly proportion.
Volume increase → T° increase
Volume decrease → T° decrease
Let's go to the maths
P₁ / T₁ = P₂/T₂
100 kPa / 333K = P₂ / 283K
(100 kPa / 333K) . 283K = P₂ → 84.9 atm
As T° has decreased, pressure also decreased.
Explanation:
Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. ... This extra carbon dioxide is lowering the ocean's pH, through a process called ocean acidification.
Momentum is the product of the mass of a given body and its velocity therefore a body at rest has zero momentum.
Mathematically; momentum = velocity (in m/s) × mass (in kilograms)
therefore, reversing the formula:
mass will be given by the momentum divided by the velocity of the body
thus;
3.2 kg*m/s ÷ 762 m/s =0.0041995 kg
which is approximately 0.0042 kg (4 decimal places) or 4.2 grams (1000 g =
1 kg).
The solution would be like
this for this specific problem:
<span>(78.6 kJ) / (92.0 g /
(46.0684 g C2H5OH/mol)) = 39.4 kJ/mol </span>
<span>39.3 </span>
So the approximate molar
heat of vaporization of ethanol in kJ/mol is 39.3.
I hope this answers your question.
For an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane, the kovats retention index is mathematically given as
I = 807.857
<h3>What is Kovats
retention index?</h3>
Generally, the equation for the Kovats index(i) is mathematically given as
Therefore
I = 100[ 1+8*(0.991/1.12)]
I = 807.857
In conclusion, Kovats retention index
I = 807.857
Read more about Arithmetic
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