Question

The wall of a large room is covered with acoustic tile in which small holes are drilled 4.6 mm from center to center. How far can a person be from such a tile in meters and still distinguish the individual holes, assuming ideal conditions, the pupil diameter of the observer's eye to be 4.0 mm, and the wavelength of the room light to be 550 nm?

Answer 1

Answer:

L= 27.42m

Explanation:

We have the variables

$D=4.6*10^{-3}m$

$d= 4*10^{-3}m$

$\lambda = 550*10^{-9}m$

Use the relation,

$L=\frac{D}{\theta_R} = \frac{D_d}{1.22\lambda}$

$L= \frac{(4.6*10^{-3}m)(4*10^{-3}m)}{1.22(550*10^{-9}m)}$

$L= 27.42m$