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Nina [5.8K]
3 years ago
9

If an object is moving with_____

Physics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

Constant Velocity

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The peak luminosity of a white dwarf supernova is around 1010 Lsun, and it remains brighter than 108 Lsun for about 150 days. In
Airida [17]

Answer:

Explanation: find the attached solution below

8 0
3 years ago
What volume will be occupied by 20g of Copper if the density of Copper is 9.1g/ml?
Eva8 [605]

Answer:

The volume of copper is 2.198 ml

Explanation:

Given;

mass of copper, m = 20 g

density of copper, ρ = 9.1 g/ml

Density is given by;

Density = mass / volume

Volume = mass / density

Volume = (20 g) / (9.1 g/ml)

Volume = 2.198 ml

Therefore, the volume of copper is 2.198 ml

3 0
3 years ago
A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at
zavuch27 [327]
In order to calculate the electric field strength, we may use the formula:
E = kQ/d²
Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:
E = (9 x 10⁹)(8.7 x 10⁻⁹) / (3.5²)
E = 6.39 Newtons per coulomb

Therefore, the answer is 6.4 Newtons/coulomb
8 0
3 years ago
A football is thrown from the edge of a cliff from a height of 22 m at a velocity of 18 m/s [39degrees above the horizontal]. A
mihalych1998 [28]

Answer:

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff  2 s later. Thus, it is not possible for the player to catch the ball.

Explanation:

Given;

vertical height of the cliff, h = 22 m

velocity of the ball, u = 18 m/s at an angle 39⁰

vertical component of the velocity, u_y = u \ sin  \theta

The time for the ball to get to the bottom of the cliff is calculated as;

h = ut + ¹/₂gt²

h = (u sinθ)t + ¹/₂ x 9.8 x t²

22 = (18 sin 39)t + 4.9t²

22 = 11.328t + 4.9t²

4.9t² + 11.328t  - 22 = 0

Solve the above equation with formula method;

a = 4.9, b = 11.328, c = -22

t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-11.328\ \ +/- \ \ \sqrt{(-11.328)^2 - 4(4.9\times -22)} }{2(4.9)}\\\\t = 1.26 \ s

The time for the player to get to the bottom of the cliff;

Given maximum speed, Vx = 6.0 m/s and horizontal distance, X = 12 m;

t = \frac{X}{V_x} \\\\t = \frac{12}{6} \\\\t = 2 \ s

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff 2 s later. Thus, it is not possible for the player to catch the ball.

7 0
2 years ago
A motorcycle moving 18.8 m/s has<br> 57800 J of KE. What is its mass?<br> (Unit = kg)
Nady [450]

Answer:10

Explanation:

3 0
3 years ago
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