They both represent equations, they both use lines
Answer:
10.875 miles
So 87 minutes
.125 miles per minute
So just multiply int his case
87*.125
You’d get 10.875
Answer:
The percentage yield of LiOH is 39.9%
Explanation:
From the question given above, the following data were obtained:
Theoretical yield = 47.4 g
Actual yield = 18.9 g
Percentage yield =?
The percentage yield of LiOH can be obtained as follow:
Percentage yield = Actual yield / Theoretical yield × 100
Percentage yield = 18.9 / 47.4 × 100
Percentage yield = 1890 / 47.4
Percentage yield = 39.9%
Therefore, percentage yield of LiOH is 39.9%
<span>CHCl3 because there are more than two atoms in this molecule that are different. Hydrogen has a small electron cloud and occupies less space, where Cl has a larger electron cloud and occupies more space, this would make it different than the expected tetrahedron shape.</span>
Answer:
BaI₂.5H₂O
Explanation:
Given Data:
Mass of Hydrated BaI₂ = 10.222 g
Mass of dried BaI₂ = 9.520 g
Mass of Water removed = 10.222-9.520 = 0.702 g
M.Mass of BaI₂ = 391.136 g/mol
M.Mass of Water = 18.02 g/mol
Now,
Calculate moles of dried BaI₂ as,
Moles = Mass / M.Mass
Moles = 9.520 g / 391.136 g/mol
Moles = 0.02434 moles
Calculate moles of Water as,
Moles = Mass / M.Mass
Moles = 0.702 g / 18.02 g/mol
Moles = 0.0389 moles
Then,
Calculate Mole ratio of BaI₂ and water as,
= 0.02434 moles BaI₂ / 0.0389 moles Water
= 0.625
Now,
We will convert this mole ratio to a whole number by multiplying it with a nearest integer,
= 0.625 × 8
= 5
Hence, this means for every one mole of BaI there are 5 moles of Water.
Result:
BaI₂.5H₂O