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4 years ago

Solve the inequality for x in the expression 8x>56

Mathematics

2 answers:

alisha [4.7K]4 years ago

7 0

Answer:

its 8 because 8×7=56. it's the next multiple

11111nata11111 [884]4 years ago

6 0

Answer:

To solve the inequality for x you need to get x by itself

To do this you need to do the opposite of the operation that is being done to your variable

8x>56 (8 is being multiplied by x, so we need to divide to get rid of the 8)

x>7 (8/8=1, 56/8=7) You keep the sign facing the same way

x>7

Hope this helps ;)

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A student earned grades of B, B, A, C, and D. Those courses had these corresponding numbers of credit hours: 4, 5, 1, 5, 4.

DiKsa [7]

Answer:

Computation of Grade Point Average (GPA):

GPA = Total Weighted Points divided by total credit hours

= 45/19

= 2.37 on 4.00 Grade Average

Step-by-step explanation:

a) Data and Computations:

Courses Grade Letters Credit Hours Quality Points Weighted Points

1 B 4 3 12

2 B 5 3 15

3 A 1 4 4

4 C 5 2 10

5 D 4 1 4

Total 19 credit hours 45 Points

b) GPA = Total Weighted Points divided by total credit hours

= 45/19

= 2.37

c) The GPA for this student is the total weighted points (which is a product of the credit hours (loads) and the quality point) expressed as a ratio of the total credit hours for the courses she took. The grade point average ensures that the each point used in calculating the GPA is weighed by the credit hours allocated to the course. The resultant figure of 2.37 implies that out of 4.00 grade points, the student scored 2.37, translating to about 59%.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

2 years ago

Thanks for the help

Goshia [24]

Your answer is 21.98

6 0

3 years ago

I need help with one more and can you explain how it works too thank you

notka56 [123]

The answer to this question is 5.2

8 0

3 years ago

Drop downs are for the first one

mixas84 [53]

Answer:

According to Angle Bisector Theorem, if Ray YZ is an angle bisector, then MZ and NZ are congruent.

EH= 23. It is shown that ray FH bisects EFG, EF and EH are perpendicular, FG and HG are perpendicular. Then EH and GH are congruent. Therefore since GH= 23, then EH= 23

8 0

3 years ago