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svet-max [94.6K]
3 years ago
10

What is the IUPAC name of the following compound? There is a structure for an organic molecule. It has 6 carbons in its chain, a

–CH3 group attached to the second (from left to right) carbon, and a double bond between the fifth and the sixth carbons.

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

Process

1.- Look for the longest chain

2.- Number the carbons of the main chain starting from the corner where the double bond is closer.

3.- Circle the branches

4.- Start naming the number where the branch is and the name of the branch.

5.- Name the main branch with the ending -ene.

                    5-methyl, 1-hexene or 5-methyl, hex-1-ene

See gthe structure below.

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Electrolysis hydrocloric acid and both of the electrode uses a platinium electrode... what will happen to both of the electrode?
Rasek [7]

Answer:

Hydrogen gas  is evolved at the cathode and chlorine gas at the anode.

Explanation:

The solution will ionise.  Hydrogen ions, H+, will migrate to  the negative cathode ( where the current leaves the solution and chloride ions Cl- will migrate the the positive anode.

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Answer:

Explanation:

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Read 2 more answers
A 420 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 7 mL of 1.00 M KOH. What is the pH following this addition
Art [367]

<u>Answer:</u> The pH of the resulting solution will be 3.60

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ......(1)

We are given:

Molarity of formic acid = 0.100 M

Molarity of potassium formate = 0.100 M

Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

\text{Moles of formic acid}=(0.100mol/L\times 0.420L)=0.0420mol

\text{Moles of potassium formate}=(0.100mol/L\times 0.420L)=0.042mol

Molarity of KOH = 1.00 M

Volume of solution = 7 mL = 0.007 L

Putting values in equation 1, we get:

\text{Moles of KOH}=(1mol/L\times 0.007L)=0.007mol

The chemical equation for the reaction of formic acid and KOH follows:

                 HCOOH+KOH\rightleftharpoons HCOOK+H_2O

I:                   0.042     0.007       0.042

C:                -0.007    -0.007     +0.007

E:                  0.035         -           0.049

Volume of solution = [420 + 7] = 427 mL = 0.427 L

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}} .......(2)

Given values:

[HCOOK]=\frac{0.049}{0.427}

[HCOOH]=\frac{0.035}{0.427}

pK_a=3.75

Putting values in equation 2, we get:

pH=3.75-\log \frac{(0.049/0.427)}{(0.035/0.427)}\\\\pH=3.75-0.146\\\\pH=3.60

Hence, the pH of the resulting solution will be 3.60

6 0
3 years ago
What is the symbol for an atom containing 20 protons and 22 neutrons?
k0ka [10]

Answer:

Calcium

Explanation:

4 0
3 years ago
Please help!
adoni [48]

2. 15.65 grams of KCl is formed if 25.0 g of Potassium Chlorate, KClO3, decompose.

3. 2.17 moles of H2 gas produced when 100.0 grams of Na is added to the reaction.

4. 7.5 moles of Hydrogen, H2, are needed to react with 2.5 moles of Nitrogen, N2.

Explanation:

2. The balanced equation for the chemical reaction is:

2KClO3 ⇒ 2KCl + 3O2

Data given:

mass of KClO3 = 25 grams, atomic mass of KClO3 = 122.55 grams/mole

KCl produced =?  atomic mass of KCl = 74.55

number of moles = \frac{mass}{atomic mass of one mole}

                              = \frac{25}{122.55}

  number of moles = 0.20 moles of KCO3

2 moles of KClO3  decomposes to give 2KCl

0.21 moles of KClO3 decomposes to give x moles of KCl

\frac{2}{2} = \frac{x}{0.21}

x = 0.21 moles of KCl

mass of KCl = 0.21 x 74.55

                     = 15.65 grams of KCl is formed.

3. data given:

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

mass of Na added = 100 grams, atomic mass of Na = 22.98 grams/mole

moles of H2 =?

Number of moles of Na = \frac{mass}{atomic mass of one mole}

                            = \frac{100}{22.98}

         number of moles of Na = 4.35 moles

2 moles of Na gives 1 mole of H2

4.35 moles of Na will give x moles

\frac{1}{2} = \frac{x}{4.35}

2x = 4.35

x = 2.17 moles of hydroden gas is produced.

4. Data given:

the balanced chemical equation:

N2 + 3H2 → 2NH3

Number of moles of N2 2.5

from the reaction

1 mole of N2 reacts with 3 moles of H2

The molar ratio of the reactant is 1:3

so, \frac{1}{3}= \frac{2.5}{x}

x = 7.5 moles of H2 will react with 2.5 moles of N2.

7 0
3 years ago
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