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svet-max [94.6K]
3 years ago
10

What is the IUPAC name of the following compound? There is a structure for an organic molecule. It has 6 carbons in its chain, a

–CH3 group attached to the second (from left to right) carbon, and a double bond between the fifth and the sixth carbons.

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

Process

1.- Look for the longest chain

2.- Number the carbons of the main chain starting from the corner where the double bond is closer.

3.- Circle the branches

4.- Start naming the number where the branch is and the name of the branch.

5.- Name the main branch with the ending -ene.

                    5-methyl, 1-hexene or 5-methyl, hex-1-ene

See gthe structure below.

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Explanation:

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6 0
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Which of the following sentences represents a physical change? sugar dissolves in coffee iron rusts gasoline burns in an engine
MAXImum [283]

<u><em>Answer:</em></u>

  • Physical changes example is sugar dissolves in coffee
  • Chemical changes examples are iron rusts, gasoline burns in an engine and a candle burns.

Explanation.

  • Physical changes depend on only physical state, not on composition, which can be separated by physical means while chemical changes depend on composition and only separated by chemical ways.
  • As in case of iron rusting, gasoline and candle burn are cases chemical changes bcz they convert into another substance whose composition is different from other as compare to sugar which has same composition in coffee ,only state is changed from solid to liquid.

6 0
3 years ago
Read 2 more answers
An unknown solution has a ph of 2. How would you classify this solution
sammy [17]
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3 years ago
A sample of carbon dioxide occupies a volume of 2.50L liters at 300kPa pressure and a temperature 273K. What pressure would the
Drupady [299]

Answer:

The answer to your question is:    P2 = 846 kPa

Explanation:

Data

V1 = 2.5 l

P1 = 300 kPa

T1 = 273 °K

P2 = ?

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T2 = 308°K

Formula

             \frac{P1V1}{T1}  = \frac{P2V2}{T2}

             P2 = \frac{P1V1T2}{T1V2} \\

             P2 = \frac{(300)(2.5)(308)}{(273)(1)} \\

            P2 = \frac{231000}{273} \\

            P2 = 846 kPa

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