Answer:
11 molecules of CH4.
23 atoms of C is the leftover.
Explanation:
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In this case, for the formation of methane:
We can see there is an excess of carbon based on their stoichiometry, because the needed amount of hydrogen gas molecules would be:
Thus, the formed molecules of methane are computed below:
In such a way, the leftover of carbon atoms are:
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Answer : The molecular weight of this compound is 891.10 g/mol
Explanation : Given,
Mass of compound = 12.70 g
Mass of ethanol = 216.5 g
Formula used :
where,
= change in freezing point
= temperature of pure ethanol =
= temperature of solution =
= freezing point constant of ethanol =
i = van't hoff factor = 1 (for non-electrolyte)
m = molality
Now put all the given values in this formula, we get
Therefore, the molecular weight of this compound is 891.10 g/mol
Answer:
The maximum kinetic energy of electron is = 2.93 × Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × J s
c = speed of light = 3 ×
= 261 nm = 261 ×
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron =
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule
hybridization is defined as mixing up of the atomic orbital with nearly same energies according to linear combination of atomic orbitals. the orbitals formed are equal in energy and are called hybrid orbitals .
