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MrRa [10]
2 years ago
10

A photon has a wavelength of approximately 2 x 10-7m. What is the energy, in joules, associated with this photon?

Chemistry
1 answer:
kaheart [24]2 years ago
4 0

Answer:

E = 9.95×10⁻¹⁹ J

Explanation:

Given data:

Wavelength = 2×10⁻⁷ m

Energy of photon = ?

Solution:

Formula:

E = hc/λ

h = 6.63×10⁻³⁴ Js

c = 3×10⁸ m/s

by putting values,

E =  6.63×10⁻³⁴ Js × 3×10⁸ m/s / 2×10⁻⁷ m

E = 19.89×10⁻²⁶Jm / 2×10⁻⁷ m

E = 9.95×10⁻¹⁹ J

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serg [7]

Answer:

Explanation:

3

Explanation:

The reaction expression is given as:

     Al(OH)₃  +   HNO₃   →    H₂O   +  Al(NO₃)₃  

To solve this problem, let us assign coefficient a,b,c and d to each specie;

          aAl(OH)₃  +   bHNO₃   →    cH₂O   +  dAl(NO₃)₃  

Conserving Al : a  = d

                  O:  3a + 3b  = c + 9d

                  H: 3a + b  = 2c

                  N: b  = 3d

let a = 1 , d  = 1, b  = 3 , c = 3

 Multiply through by 3;

a  = 1, b  = 3, c = 3 and d  = 1

  Al(OH)₃  +   3HNO₃   →    3H₂O   +  Al(NO₃)₃  

7 0
2 years ago
Read 2 more answers
How many grams of diphosphorus pentoxide result if 100.0 g of phosphorus are combined with sufficient oxygen?
gregori [183]
Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.
3 0
3 years ago
Number of moles in 31.99g O2 <br> And 176.8g NaCl
sergey [27]

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

\\ \sf\longmapsto No\:of\:moles\approx 1

#NaCl

\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}

\\ \sf\longmapsto No\;of\:moles=3mol

8 0
2 years ago
What is a mixture called when it has its different components mixed evenly within the substance? Heterogeneous mixture Homogeneo
larisa86 [58]
It would be considered a Homogeneous Mixture. A mixture with two or more components mixed evenly is a Homogeneous mixture.

3 0
3 years ago
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If a gas sample has a pressure of 30.7 kPa at 0.00*C, by how much does the temperature have to decrease to lower the pressure to
Scrat [10]

Answer:

                      252.68 K  or   -20.46 °C

Explanation:

                    According to Gay-Lussac's Law, "Pressure and Temperature at given volume are directly proportional to each other".

Mathematically,

                                              P₁ / T₁  =  P₂ / T₂   ---- (1)

Data Given:

                  P₁  =  30.7 kPa

                  T₁  =  0.00 °C  =  273.15 K

                  P₂  =  28.4 kPa

                  T₂  =  <u>???</u>

Solving equation for T₂,

                  T₂  =  P₂ T₁ / P₁

Putting values,

                  T₂  =  28.4 kPa × 273.15 K / 30.7 kPa

                  T₂  =  252.68 K  or   -20.46 °C

8 0
3 years ago
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