Question

What are the solutions of this equation 16-2x^2=-64

Answer 1

Answer:

x = ± 2$\sqrt{10}$

Step-by-step explanation:

Given

16 - 2x² = - 64 ( subtract 16 from both sides )

- 2x² = - 80 ( divide both sides by - 2 )

x² = 40 ( take the square root of both sides )

x = ± $\sqrt{40}$ = ± $\sqrt{4(10)}$ = ± 2$\sqrt{10}$