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4 years ago

What are the solutions of this equation 16-2x^2=-64

Mathematics

1 answer:

xenn [34]4 years ago

5 0

Answer:

x = ± 2 $\sqrt{10}$

Step-by-step explanation:

Given

16 - 2x² = - 64 ( subtract 16 from both sides )

- 2x² = - 80 ( divide both sides by - 2 )

x² = 40 ( take the square root of both sides )

x = ± $\sqrt{40}$ = ± $\sqrt{4(10)}$ = ± 2 $\sqrt{10}$

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A right triangle has a lleg of length 16 and a hypotenuse of length 25. The length of the other leg is (Rounded to the nearest t

Wittaler [7]

Answer:

Step-by-step explanation:

1st you will use a^2+b^2=c^2

next you plug them in so it would be a^2+16^2=25^2

next you would solve it to a^2+256=625

then you would get 369 and square root it

and your answer will be 19.2.

3 0

3 years ago

If square + circle= triangle then triangle - square =? And how do you know the answer is correct?

EastWind [94]

Answer:

Circle

Step-by-step explanation:

if square plus circle is triangle then if you subtract a square from it all you have left is a circle

7 0

4 years ago

Nathan deposited 7/9 of his allowance into his savings account. He spent the remaining amount, or $2.50. How much did Nathan dep

inysia [295]

2/9=2.50
Allowence=2.50x9 divided by which gives you an answer of 11.25
Hope this helps you!

4 0

3 years ago

Find all of the points of the form (x, −x) which are 7 units from the origin.

Morgarella [4.7K]

Answer:

(-7, 0) and (7, 0)

Step-by-step explanation:

<u>All the points that are 7 units from the origin are on the circle:</u>

x² + y² = 7²

<u>The maximum and minimum values of x obtained when y = 0:</u>

x² = 7²
√x² = √7²
x = ± 7

min x = -7 and
max x = 7

<u>The points are:</u>

(-7, 0) and (7, 0)

3 0

3 years ago

Read 2 more answers

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago