The current in the wires of a circuit is 60 milliamps. If the resistance of the circuit were doubled (with no change in voltage)
, then it’s new current would be _____ milliamps
1 answer:
Answer:30
Explanation:
Current=60 milliamps
Current=(voltage)/(resistance)
60=(voltage)/(resistance)
Doubling the resistance means multiplying both sides by 1/2
60x1/2=(voltage)/(resistance) x 1/2
30=(voltage)/2(resistance)
Therefore the resistance would be 30 milliamp if we double the resistance
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