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polet [3.4K]
3 years ago
15

The current in the wires of a circuit is 60 milliamps. If the resistance of the circuit were doubled (with no change in voltage)

, then it’s new current would be _____ milliamps
Physics
1 answer:
anygoal [31]3 years ago
8 0

Answer:30

Explanation:

Current=60 milliamps

Current=(voltage)/(resistance)

60=(voltage)/(resistance)

Doubling the resistance means multiplying both sides by 1/2

60x1/2=(voltage)/(resistance) x 1/2

30=(voltage)/2(resistance)

Therefore the resistance would be 30 milliamp if we double the resistance

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natita [175]

Question : 1

  • mass (m) = 1000 kg
  • velocity (v) = 5 m/s

=》

k.e =  \dfrac{1}{2}mv {}^{2}

=》

k.e =  \dfrac{1}{2}  \times 1000 \times (5) {}^{2}

=》

k.e = 500 \times 25

=》

k.e = 12500 \: joules

kinetic energy = 12500 joules

Question : 2

  • mass (m) = 10 kg
  • velocity (v) = 5 m/s

=》

k.e =  \dfrac{1}{2} mv {}^{2}

=》

k.e = \dfrac{1}{2}  \times 10 \times  ({5})^{2}

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k.e = 5 \times 25

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k.e = 125 \: joules

kinetic energy = 125 joules

Question : 3

  • mass = 100 kg
  • velocity = 5 m/s

=》

k.e =  \dfrac{1}{2} mv {}^{2}

=》

k.e =  \frac{1}{2}  \times 100 \times (5) {}^{2}

=》

k.e = 50 \times 25

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k.e = 1250 \: joules

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8 0
3 years ago
What are the coordinates of the point that is 1/5 of the way from A(-7,-4) to B(3, 6)?
Olegator [25]

Answer:

coordinate will be

r = (1.33,4.33)

Explanation:

As we know that if a point will divide two given coordinates in m : n ratio

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x = \frac{mx_1 + nx_2}{m+n}

y = \frac{my_1 + ny_2}{m+n}

here we know that two points are

(-7, -4) and (3, 6)

and the ratio is given as 1 : 5

now from above formula we will have

x = \frac{1(-7) + 5(3)}{1 + 5} = 1.33

y = \frac{1(-4) + 5(6)}{1 + 5} = 4.33

so coordinate will be

r = (1.33, 4.33)

7 0
4 years ago
A rifle with a weight of 40 N fires a 5.5-g bullet with a speed of 220 m/s.(a) Find the recoil speed of the rifle.
liubo4ka [24]

Answer:

0.2695/s

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t = m(v-u)/F

t = 0.0055(220)/40

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v = 0+9.8(0.0275).

v = 0.2695m/s

Hence the speed of the rifle is 0.2695m/s

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3 years ago
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Answer:

question  1: force

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Let's see

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\\ \rm\Rrightarrow \alpha=-x\omega^2

Or

\\ \rm\Rrightarrow \alpha=-\omega^2x

6 0
2 years ago
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