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bearhunter [10]
3 years ago
11

How do you write 6×1+6×(1/10)+3×(1/100)+7×(1/1000) in standard form?

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

6.637

Step-by-step explanation:

Let's begin by breaking down each step in the equation.

6*1

6*1/10

3*1/100

7*1/1000

Now, let's solve each step.

6*1 = 6

6*1/10 = 0.6

3*1/100 = 0.03

7*1/1000 = 0.007

To get the final answer, add all products together.

6 + 0.6 + 0.03 + 0.007 = 6.637

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Which is the product of 7/9 and 6 in a fraction number
PIT_PIT [208]

Answer:

4 2/3

Step-by-step explanation:

7/9 multiplied by 6/1 = 42/9

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3 years ago
Arrange and write the integers in decreasing order -47, -82, 77, -48
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3 years ago
Show that n(n+1)(n+2) is divisible by 6<br>Solution<br>(​
vladimir2022 [97]

Proof by induction

Base case:

n=1: 1*2*3=6 is obviously divisible by six.

Assumption: For every n>1 n(n+1)(n+2) is divisible by 6.

For n+1:

(n+1)(n+2)(n+3)=

(n(n+1)(n+2)+3(n+1)(n+2))

We have assumed that n(n+1)(n+2) is divisble by 6.

We now only need to prove that 3(n+1)(n+2) is divisible by 6.

If 3(n+1)(n+2) is divisible by 6, then (n+1)(n+2) must be divisible by 2.

The "cool" part about this proof.

Since n is a natural number greater than 1 we can say the following:

If n is an odd number, then n+1 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.

If n is an even number" then n+2 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.

Therefore by using the method of mathematical induction we proved that for every natural number n, n(n+1)(n+2) is divisible by 6. QED.

6 0
3 years ago
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