You must use 1880 mL of O₂ to react with 4.03 g Mg.
A_r: 24.305
2Mg + O₂ ⟶ 2MgO
<em>Moles of Mg</em> = 4.03 g Mg × (1 mol Mg/24.305 g Mg) = 0.1658 mol Mg
<em>Moles of O₂</em> = 0.1658 mol Mg × (1 mol O₂/2 mol Mg) = 0.082 90 mol O₂
STP is 25 °C and 1 bar. At STP, 1 mol of an ideal gas has a volume of <em>22.71 L</em>.
<em>Volume of O₂</em> = 0.082 90 mol O₂ × (22.71 L O₂/1 mol O₂) = 1.88 L = 1880 mL
Answer:
im not completely sure but the mst likely answer would be the would be they have the same density
Explanation:
if two mixture have the same ingriedients their most likely going to have the same density depending of the measurements like when baking a cake when you add your wet ingriedients to your dry one it makes a batter and if you were to make another mixture with the same ingriedients and somewhat similar measurements your going to get a similar density
Physical change
Giddy Up!!!!!
The third one
synthesis reactions have multiple reactants that synthesize into one product