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san4es73 [151]
3 years ago
6

Which of these choices is the correct net ionic equation for the reaction that occurs when solutions of pb(no3)2 and nh4cl are m

ixed?
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
4 0
Pb(NO₃)₂ + 2NH₄Cl = PbCl₂(s) + 2NH₄NO₃
Pb²⁺ + 2NO₃⁻ + 2NH₄⁺ + 2Cl⁻ = PbCl₂ + 2NH₄⁺ + 2NO₃⁻
Pb²⁺ + 2Cl⁻ = PbCl₂
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An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

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