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ehidna [41]
3 years ago
6

You drank 8/9 cups of orange juice with your breakfast. If this is 2/3 of the amount that was in the container, how much was in

the container?
Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

1  1/3 cups of juice

Step-by-step explanation:

Let the volume of the container be c, which is measured in cups.

Then (2/3)c = (8/9) cups juice.  We must solve this for the container volume, c.

      (8/9) cups

c = ----------------

           2/3

Inverting the divisor (2/3) and multiplying, we get:

      3(8/9 cups)

c = ------------------ =  12/9 cups, or 4/3 cups, or 1 1/3 cups.

             2

The container originally held 1 1/3 cups of joice.

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20) The volume of a cone is 1871 cubic feet. If the height of the cone is 6 ft, what is the radius of the cone? (V =
Andrew [12]

Answer:

C

Step-by-step explanation:

Good Luck and I hope you do well :)

5 0
2 years ago
How do i do this? im bad at math..
Andreyy89

Answer:

X is equal to 6

Step-by-step explanation:

2 times 6 is 12

6 plus 2 is 8

4 0
2 years ago
Read 2 more answers
5=5ax+1 please help, its due in an hour.<br><br> solve for x
RUDIKE [14]

Answer:

x= 4/5a

Step-by-step explanation:

5=5/ax+1

Step 1: Multiply both sides by a.

5a=a+5x

Step 2: Flip the equation.

a+5x=5a

Step 3: Add -a to both sides.

a+5x+−a=5a+−a

5x=4a

Step 4: Divide both sides by 5.

5x/5=4a/5

x= 4/5a

Hope this helps!

4 0
3 years ago
Ik I said one more buh I assure u this is the last :p
Dmitriy789 [7]
Here you go this took me time

3 0
3 years ago
Work out the area of the trapezium ABDE.<br> B<br> 9 cm<br> 6 cm<br> 8 cm<br> →D<br> E
Evgen [1.6K]

Answer:

Area of the trapezium ABDE = 30 cm²

Step-by-step explanation:

Area of a trapezium = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the trapezium

h = Distance between the parallel sides

From the picture attached,

ΔCAE and ΔCBD are the similar triangles.

So by the property of similarity their sides will be proportional.

\frac{AE}{BD}= \frac{CE}{CD}

\frac{9}{6}=\frac{CE}{8}

CE = \frac{9\times 8}{6}

CE = 12 cm

Therefore, DE = CE - CD

DE = 12 - 8 = 4 cm

Now area of trapezium ABDE = \frac{1}{2}(AE+BD)(DE)

                                                  = \frac{1}{2}(6+9)4

                                                  = 30 cm²

Therefore, area of the trapezium ABDE = 30 cm²

8 0
3 years ago
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