Answer:
1/2
Step-by-step explanation:
● 1/4 + 4(1/2 - 3/4 )^2
To make it easier convert the fractions to decimal numbers.
● 1/4 = 0.25
● 1/2 = 0.5
● 3/4 = 0.75
So the expression will be:
● 0.25 + 4(0.5 - 0.75)^2
Calculte first 0.5-0.75 (0.5-0.75= -0.25)
● 0.25 + 4 × (-0.25)^2
-0.25^2 is the same as 0.25^2
● 0.25 + 4 × (0.25)^2
0.25^2 is 0.0625
● 0.25 + 4×0.0625
Multiplication has the priority (4 ×0.0625) wich is 0.25
● 0.25 + 0.25
● 0.5
0.5 is 1/2
So the answer 1/2
Answer:
The point estimate for the number of pieces per package is of 18.72.
Step-by-step explanation:
Point estimate of a population mean:
The mean of the sample gives an estimate for the population mean.
They find that the sample mean number of pieces is 18.72.
This means that the point estimate for the number of pieces per package is of 18.72.
Answer:
hello attached below is the detailed solution
answer : In |x+1| + [2/(x+1)] + [1/(1+x)^2] - [y^2/2(1+x)^2] = 5/2
Step-by-step explanation:
Given
(x^2 + y^2 - 3) dx = ( y + xy ) dy, y(0) = 1
solving the given initial-value problem
Answer:
Step-by-step explanation:
The missing figure is attached.
For this exercise you can divide the given figure into three rectangles.
The formula for calculate the area of a rectangle is:
![A=lw](https://tex.z-dn.net/?f=A%3Dlw)
Where "l" is the lenght and "w" is the width.
Knowing this, you can calculate the area of each rectangle.
Then:
Area of the Rectangle A
You can identify that:
![l_A=4\ ft\\w_A=2\ ft](https://tex.z-dn.net/?f=l_A%3D4%5C%20ft%5C%5Cw_A%3D2%5C%20ft)
Then, its area is:
![A_A=(4\ ft)(2\ ft)\\\\A_A=8\ ft^2](https://tex.z-dn.net/?f=A_A%3D%284%5C%20ft%29%282%5C%20ft%29%5C%5C%5C%5CA_A%3D8%5C%20ft%5E2)
Area of the Rectangle B
Observe that:
![l_B=4\ ft+2\ ft=6\ ft\\w_B=2\ ft](https://tex.z-dn.net/?f=l_B%3D4%5C%20ft%2B2%5C%20ft%3D6%5C%20ft%5C%5Cw_B%3D2%5C%20ft)
Then, its area is:
![A_B=(6\ ft)(2\ ft)\\\\A_B=12\ ft^2](https://tex.z-dn.net/?f=A_B%3D%286%5C%20ft%29%282%5C%20ft%29%5C%5C%5C%5CA_B%3D12%5C%20ft%5E2)
Area of the Rectangle C
You can identify that:
![l_C=5\ ft\\w_C=2\ ft](https://tex.z-dn.net/?f=l_C%3D5%5C%20ft%5C%5Cw_C%3D2%5C%20ft)
Then, its area is:
![A_C=(5\ ft)(2\ ft)\\\\A_C=10\ ft^2](https://tex.z-dn.net/?f=A_C%3D%285%5C%20ft%29%282%5C%20ft%29%5C%5C%5C%5CA_C%3D10%5C%20ft%5E2)
Add the area of the rectangles in order to find the total area. This is:
![Total=8\ ft^2+12\ ft^2+10\ ft^2\\\\Total=30\ ft^2](https://tex.z-dn.net/?f=Total%3D8%5C%20ft%5E2%2B12%5C%20ft%5E2%2B10%5C%20ft%5E2%5C%5C%5C%5CTotal%3D30%5C%20ft%5E2)
Therefore, you will need
of outdoor carpet for that hole.
Answer:
1
Step-by-step explanation: