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3 years ago

What is the remainder when (3x^4+2x^3-x^2+2x-19)÷(x+2)

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

I believe the remainder would be 5.

Hope this helps!

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Step-by-step explanation:

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Genrish500 [490]

Answer:

The surface area of the gift box is = $A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}$

Step-by-step explanation:

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$A=2\pi rh+2\pi r^2$

in this case, r is not a number, but rather an expression, which is r = $3x +1$ .

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$A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}$

$A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}$

$A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}$

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3 years ago

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Delvig [45]

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