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posledela
3 years ago
8

Richard has $1,089.26 in his checking account at the end of the month. During the month, he withdrew $120, deposited a check for

$325, and wrote one check for $425 and one check for $24.10. What was his checking account balance at the beginning of the month?
$845.16
$1,093.36
$1,333.36
$1,490.16
Mathematics
2 answers:
Stella [2.4K]3 years ago
4 0

The real <u>correct</u> answer is 132.45.

mixas84 [53]3 years ago
3 0
<span>$1,490.16 just add.........................

</span>
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32 15' 66" is the same as _____. Round to the nearest hundredth of a degree. Answer:
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First, convert 15'66'' to degrees. Every degree is 60' and every minute (') is 60''. Thus,                             15' x (1° / 60') = 0.25°and                             66'' x (1' / 60'') x (1° / 60') = 0.01833°Add all the measurements in degrees including the 32° from the given. That is,                                     32° + 0.25° + 0.01833° = 32.268°Rounding the answer to the nearest hundredth gives us 32.27°.
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3 years ago
Read 2 more answers
A triangle has sides lengths of 9 cm, 12 cm, and 15 cm.
Sever21 [200]

Answer:

  • Yes it is a right triangle
  • The side lengths satisfy the Pythagorean theorem equation

Step-by-step explanation:

We can test these numbers to see if they satisfy the Pythagorean theorem equation:

  15² = 9² + 12²

  225 = 81 + 144 . . . . true

Since the numbers satisy the Pythagorean theorem relation, they belong to a right triangle.

____

You can recognize that the ratio of side lengths is ...

  9 : 12 : 15 = 3 : 4 : 5

Further, you can recognize that the side lengths 3, 4, 5 belong to the right triangle with the smallest integer side lengths that satisfy the Pythagorean theorem. Hence the 9 : 12 : 15 triangle is similar (by a scale factor of 3) to a right triangle, thus is a right triangle.

8 0
4 years ago
Which situation is best modeled by the expression 1/2 x 1/6.
yanalaym [24]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]
blagie [28]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

3 0
3 years ago
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