Answer:
y = -4
Step-by-step explanation:
12y + 4 = 8y-12
Subtract 8y from each side
12y - 8y +4 = -12
4y +4 = -12
Subtract 4 from each side
4y +4-4 = -12 -4
4y = -16
Divide by 4
4y/4 = -16/4
y = -4
Have you learned matrices yet? I'm going to use that to solve these, please refer to the photos.
I solved the system by using a matrix calculation. The work always needs to be shown and you do that by setting up the matrix like in the first photo and also writing out all your equations. In a TI calculator, to do this you press 2ND-X^-1,GO TO EDIT - [A] - 3×4- now enter the coefficient of the system of equations variables. NOW 2ND MODE- 2ND-X^-1 -GO TO MATH- ALPHA APPS
Now, if you don't know this you may be confuse so after rref([A]) was enter a matrix came up with [1 0 0 -21] in the top row this means x equal -21. So, the next row is y and it came out as [0 1 0 46] so y equals 46 and I'm going to let you figure out what z is by looking at the matrix.
SO... X=-21 Y=46 and Z=-10
Let's Test it
Answer:
1^15 is 15
Step-by-step explanation:
Answer:
8.95feet
Step-by-step explanation:
The set up is a right angled triangle where;
The camera's horizontal distance from the focus point = 26feet = Adjacent;
The height of the camera above the floor = Opposite = x
Angle of elevation = 19°
According to TOA in trig identity;
Tan theta = opp/adj
Tan 19 = x/26
x = 26tan 19
x = 26(0.3443)
X = 8.95feet
Hence the camera is placed at a height of 8.95feet above the floor
Answer:
C
You have to check which of numbers is the lowest.
Cheers :D