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eimsori [14]
3 years ago
10

When is the force on a current carrying wire in a magnetic field at its strongest

Physics
1 answer:
user100 [1]3 years ago
3 0
The answer is gravity my friend. :
)
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During a race, a runner runs at a speed of 6 m/s. Four seconds later, she is running at a speed of 10 m/s. what is the runners a
Georgia [21]
<span>a = (v2 - v1)/t = (10 - 6)/2 = 2 m/sec/sec (average acceleration)</span>
8 0
4 years ago
Pls help :/
vodomira [7]

Answer:

Gravitational attraction of the sun.

Explanation:

Gravity is an attractive force. Any two masses will exert an attractive force on the other according to Newton's law of universal gravitation. The more massive the objects, the stronger the force. The sun, as you can probably guess, is pretty massive - 330,000 times more than Earth, and 1,048 time more than Jupiter, our solar system's largest planet. Just like man-made satellites around Earth, the planets in our solar system are constant process of "falling" around the sun, locked in their orbits by its mass, but slowing dramatically in their orbital velocity the further away they are.

6 0
3 years ago
Name two types of evidence used to support the theory of evolution. Explain how scientists use each type of evidence to provide
bearhunter [10]
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7 0
3 years ago
What role does activation energy play in an exothermic reaction?
Nuetrik [128]

Answer A material that decreases the rate of a reaction. The amount of energy that reactants must absorb before a chemical reaction will start also called free energy of activation. What role does activation energy pay in chemical reactions? Activation energy is the energy absorbed before it can start a chemical reaction.

Explanation:

3 0
3 years ago
An electron is moving through a magnetic field whose magnitude is 9.21 × 10^-4 T. The electron experiences only a magnetic force
Marysya12 [62]

Answer:

\theta=10.60^{\circ}

Explanation:

Given that,

Magnetic field, B=9.21\times 10^{-4}\ T

Acceleration of the electron, a=2.3\times 10^{14}\ m/s^2

Speed of electron, v=7.69\times 10^{6}\ m/s

The force due to this acceleration is balanced by the magnetic force as :

ma=qvB\ sin\theta

sin\theta=\dfrac{ma}{qvB}

sin\theta=\dfrac{9.1\times 10^{-31}\times 2.3\times 10^{14}}{1.6\times 10^{-19}\times 7.69\times 10^{6}\times 9.21\times 10^{-4}}

\theta=10.60^{\circ}

So, the angle between the electron's velocity and the magnetic field is 10.6 degrees. Hence, this is the required solution,

8 0
4 years ago
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