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stepan [7]
3 years ago
5

Name two types of evidence used to support the theory of evolution. Explain how scientists use each type of evidence to provide

support for evolution. Give one example of each.
Physics
1 answer:
bearhunter [10]3 years ago
7 0
Well, one of the theories was that Charles darwin proved that theory evolution is real so that one theory. 
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PLS HELP! WILL MARK BRANLIEST!!!
Finger [1]

Answer:

d. epicentral distance scale

Explanation:

The depth of focus from the epicenter, called as Focal Depth, is an important parameter in determining the damaging potential of an earthquake. Most of the damaging earthquakes have shallow focus with focal depths less than about 70km. Distance from epicenter to any point of interest is called epicentral distance

7 0
4 years ago
a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?
evablogger [386]
<h2>Hello!</h2>

The answer is: 8.62m

<h2>Why?</h2>

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

E=PE+KE

Where:

PE=m.g.h

KE=\frac{1*m*v^{2}}{2}

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

KE_{1}+PE_{1}=KE_{2}+PE_{2}

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}

So,

h_{2}=\frac{1*m*v_{1} ^{2}}{2*m*g}\\h_{2}=\frac{1*v_{1} ^{2}}{2g}=\frac{(\frac{13m}{s})^{2} }{2*\frac{9.8m}{s^{2}}}\\h_{2}=8.62m}

Hence,

The height at the second moment (maximum height) is 8.62m

Have a nice day!

5 0
4 years ago
20 points ! Help!!! Please and thank you !
Delvig [45]

Number 7is 64. 8 is 486 because 3 to the 5th is 243 then multiply by 2.

9 is 1003.092

10. Is 5

4 0
4 years ago
Read 2 more answers
A Ferris wheel has radius 5.0 m and makes one revolution every 8.0 s with uniform rotation. A person who normally weighs 670 N i
DaniilM [7]

Answer:

The apparent weight of the person as she pass the highest point is  N  =  458.8 \ N

Explanation:

From the question we are told that

   The radius of the Ferris wheel is r = 5.0 \ m

    The period of revolution is T = 8.0 \ s

     The weight of the person is  W  =  670 \ N

   

Generally the speed of the wheel is mathematically represented as

      v =  \frac{2 \pi r}{T }

substituting values

      v =  \frac{2 * 3.142 *  5}{8 }

       v =  3.9 3 \ m/s

The apparent weight (the normal force exerted on her by the bench) at the highest point is mathematically evaluated as

          N  =  mg  - \frac{mv^2}{r}

Where m is the mass of the person which is mathematically evaluated as

     m =  \frac{W}{g}

substituting values

    m =  \frac{670}{9.8}

    m =  68.37 \ kg

So

    N  =  68.37 * 9.8   - \frac{68.37 * {3.93}^2}{5}

    N  =  458.8 \ N

5 0
3 years ago
How to add an answer
netineya [11]
You cannot add an answer if two people are already answering!
7 0
3 years ago
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