1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anon25 [30]
3 years ago
5

How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t

hat there is excess Xe. Xe(g) +3F2(g)→XeF6(g) A) 8.25 × 1023 molecules XeF6 B) 1.21 × 1023 molecules XeF6 C) 1.37 × 1023 molecules XeF6 D) 7.29 × 1023 molecules XeF6 E) 2.75 × 1023 molecules XeF6
Chemistry
1 answer:
ddd [48]3 years ago
8 0

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

You might be interested in
Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He
marysya [2.9K]

Answer:

140

Explanation:

4 0
3 years ago
Read 2 more answers
Twenty five grams of Iron 3 oxide react with an excess of carbon monoxide to form 15 g of Fe. Carbon dioxide is the other produc
densk [106]
<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

                                     = 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

                              = 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

            = (15 g ÷ 17.42 g) × 100 %

            = 86.11%

7 0
3 years ago
Given the following UNBALANCED reaction: NH3 (g) &lt;--&gt; N2 (g) + H2 (g) If 1
Yakvenalex [24]

Answer:

C. 1.35

Explanation:

                                                     2NH3 (g) <-->          N2 (g) +             3H2 (g)

Initial concentration                2.2 mol/0.95L       1.1 mol/0.95L           0

change in concentration        2x                             x                           3x

                                                 -0.84 M                  +0.42M                +1.26M

Equilibrium                       1.4 mol/0.95L=1.47M        1.58 M                   1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0
2 years ago
Q3. A student wanted to make blue copper sulfate crystals from green copper carbonate powder
CaHeK987 [17]

Heat the sulfuric acid solution and adding copper carbonate in it.

<h3>Improvement require in this experiment</h3>

The method could be improved by heating sulfuric acid solution and add copper carbonate into the solution of sulfuric acid. Add the copper carbonate until it is present in excess amount. After that filter the extra amount of copper carbonate so in this way the blue copper sulfate crystals are produced.

Learn more about copper here: brainly.com/question/3157958

5 0
2 years ago
A macromolecule made up of mainly carbon and hydrogen atoms that is primarily used for energy storage and in cell membranes.
Alex787 [66]
I believe the answer is glucose
3 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following is a property of salts? (5 points)
    13·2 answers
  • A can of soda has a volume of 250 mL and a mass of 100 g? what is the density of the soda
    12·1 answer
  • In which type of reaction do two lighter nuclei combine to form one heavier nucleus?
    13·1 answer
  • Practice: How many protons, neutrons and electrons are in the following?
    6·2 answers
  • How many molecules are in 2.38g of SO2
    15·1 answer
  • In the image below, does Group A or Group B have a stronger gravitational force between the objects in the group? Give one suppo
    8·2 answers
  • What do we use to keep track of major Earth events?​
    13·1 answer
  • Why does 50 g of copper require less heat (q) than 50 g of water, in order to raise the temperature by 15 oC? (Hint - the heat c
    9·1 answer
  • When iron(III) oxide (Fe2O3) is exposed to carbon monoxide (CO) under high pressure, metallic iron (Fe) and carbon dioxide (CO2)
    9·1 answer
  • How many hydrogen atoms are present in a hydrocarbon chain of 8 carbon atoms with 3 double bonds and the rest single bonds
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!