The atomic number for iodine (I) = 53
The electron for I is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Now, among the noble gases, Krypton (Kr) has an atomic number 36. Thus we can write:
I = [1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ ] 5s² 4d¹⁰ 5p⁵
I = [Kr] 5s² 4d¹⁰ 5p⁵
(or)
I = [Kr] 4d¹⁰ 5s² 5p⁵
The answer is D. Ammonia is a weak electrolyte and a weak base. Ammonia produces ions when dissolving but remains predominantly as molecules that are not ionized. This is what makes it a weak electrolyte. Ammonia also does not fully ionize in a solution. This is what makes is a weak base.
V1/T1 = V2/T2
V1= 3.5 L
T1 = 25 +273=298 K
T2 = 40.9 + 273 = 313.9 K
V2- ?
3.5 L/298 K= V2/ 313.9 K
V2 = (3.5 L*313.9 K)/298 K ≈ 3.69 L
If its oxidised, water and carbon dioxide is formed.
In all forms of chemical bonds,the energy stored is chemical energy