Answer:
hello your question is incomplete attached below is the complete question
Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
Explanation:
Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
attached below is the remaining part of the solution
