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4 years ago

Suppose that you measure a pen to be 10.5 cm long. Convert this to meters.

2 answers:

8 0

If the pen is 10.5cm long, it is 0.105 meters. This can be worked out by considering that there are 100cm's in 1 meter, so you need to divide 10.5 by 100. You then move the decimal place 2 places to the right (because of the two zeros), which leads you to your answer of 0.105.

Pani-rosa [81]4 years ago

8 0

A pen measuring 10.5 cm long is equivalent to 0.105 meters.

<h2>Further Explanation</h2><h3>Length </h3>

Length refers to a measurement of distance. It is the distance between two points.

<h3>S.I units </h3>

The S.I. units of lengths. However, length can be measured using other units such as millimeters, centimeters, kilometers, etc.

<h3>Metric system unit of measurement </h3>

It is a system of measurement that uses units such as gram, liter, and meter to measure mass, capacity and length respectively.
This system measures length based on meters, such that all the other units of lengths are based on an inter-conversion of units in meters.

<h3>Conversion of units measuring length</h3>

1 centimeter = 10 millimeters

1 meter = 100 centimeters

1 meter = 1000 millimeters

1 kilometer = 1000 meters

1 kilometer = 1000000 centimeters, and so forth.

<h3>Conversion of larger units to small units </h3>

To convert larger units of measurement to smaller units we multiply we multiply the number of larger units by the appropriate conversion factor.

<h3>Conversion of smaller units to larger units</h3>

When converting smaller units of measurements to larger units of measurements we divide the number of smaller units by the appropriate factor.
For example, to convert cm to m, we divide the number of cm by 100.

In the question;

The pen measures 10.5 cm

But, 1 meter = 100 centimeters

Thus;

10.5 cm will be equivalent to;

= 10.5 cm/100 cm

= 0.105 meters

Therefore, a pen measuring 10.5 cm in length is equivalent to 0.105 meters.

Keywords: Length, meters, centimeters, metric unit system

<h3>Learn more about: </h3>

Conversion of centimeters to length: brainly.com/question/1616139
Metric system of measurements: brainly.com/question/1616139
Units of measuring length: brainly.com/question/1616139

Level: Middle school

Subject: Mathematics

Topic: Metric system of measurements

Sub-topic: Units of measuring length

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3 years ago

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Answer: The molecular formula for androstenedione is, $C_{19}H_{26}O_2$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=5.527g$

Mass of $H_2O=1.548g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 5.527 g of carbon dioxide, $\frac{12}{44}\times 5.527=1.507g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.548 g of water, $\frac{2}{18}\times 1.548=0.172g$ of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = $(1.893g)-[(1.507g)+(0.172g)]=0.214g$

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.507g}{12g/mole}=0.126moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.172g}{1g/mole}=0.172moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.214g}{16g/mole}=0.0133moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is $0.0133$ moles.

For Carbon = $\frac{0.126}{0.0133}=9.5$

For Hydrogen = $\frac{0.172}{0.0133}=12.9\approx 13$

For Oxygen = $\frac{0.0133}{0.0133}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9.5 : 13 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 19 : 26 : 2

Thus, the empirical formula for the given compound is $C_{19}H_{26}O_2$

The empirical formula weight of $C_{19}H_{26}O_2$ = 19(12) + 26(1) + 2(16) = 286 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{286.4}{286}=1$

Molecular formula = $C_{19}H_{26}O_2$

Therefore, the molecular formula for androstenedione is, $C_{19}H_{26}O_2$

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