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tatyana61 [14]
3 years ago
5

A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro

und with velocity of 0. -73.5 m/s , how far did the packet fall?
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m

And the negative sign means the direction of the displacement is downward.

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The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?
swat32

C is the answer

The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?

a.

It faces the moon more often than other places on Earth.

b.

It has many rocky beaches.

c.

It is a long, narrow inlet.

d.

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4 0
3 years ago
two bowling balls each have a mass of 8kg. if they are 2 m apart, what is the gravitational force between them?
Scilla [17]

Answer:

1 x 10^-9 N

Explanation:

F = Gm²/d² = 6.674e-11(8²)/2² = 1.06784e-9

4 0
2 years ago
A 19 nC charge is moved in a uniform electric field. The electric field does 5.3 μJ of work as the charge moves from point A to
Marizza181 [45]

Answer:

The potential difference between points A and B is 278.95 volts.

The potential difference between points B and C is -642.10 volts.

The potential difference between points A and C is -363.15 volts.

Explanation:

Given :

Charge of the particle, q = 19 nC = 19 x 10⁻⁹ C

Work is done to move a charge from point A to B, W₁ = 5.3 μJ

Work done to move a charge from point B to C, W₂ = -12.2 μJ

Let V₁ be the potential difference between point A and B, V₂ be the potential difference between point B and C and V₃ be the potential difference between point A and C.

The relation between work done and potential difference is:

W = qV  

V = W/q    ....(1)

Using equation (1), the potential difference between points A and B is:

V_{1}=\frac{W_{1} }{q}

Substitute the suitable values in the above equation.

V_{1} =\frac{5.3\times10^{-6} }{19\times10^{-9} }

V₁ = 278.95 V

Using equation (1), the potential difference between points B and C is:

V_{2}=\frac{W_{2} }{q}

Substitute the suitable values in the above equation.

V_{2} =\frac{-12.2\times10^{-6} }{19\times10^{-9} }

V₂ = -642.10 V

The potential difference between points A and C is:

V₃ = V₁ + V₂

V₃ = 278.95 - 642.10

V₃ = -363.15 V

8 0
3 years ago
A 10-kg piece of aluminum sits at the bottom of a lake, right next to a 10-kg piece of lead, which is much denser than aluminum.
zalisa [80]

Answer:

Aluminium

Explanation:

When a body is immersed in a liquid partly or wholly it experiences an upward force which is called buoyant force.

The amount of buoyant force depends on the volume of body immersed, density of liquid and the value of acceleration due to gravity.

Here, the density of liquid is same in both the cases and g be the same. So, here the amount of buoyant force depends on the volume of body immersed.

As the density of lead is more than the density of aluminium, so the volume of aluminium is more than lead, as volume is equal to mass divided by density. So, the buoyant force acting on the aluminium is more than lead.

7 0
3 years ago
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