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tatyana61 [14]
3 years ago
5

A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro

und with velocity of 0. -73.5 m/s , how far did the packet fall?
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m

And the negative sign means the direction of the displacement is downward.

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What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?
makkiz [27]

Answer:1.7\times 10

Explanation:

Given

Force F=7 N

time interval t=2.5 s

Impulse is given by =Force \times time\ interval\ for\ applied\ force

Impulse=7\times 2.5=17.5

For two significant Figure

Impulse=1.7\times 10

                       

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3 years ago
NO LINKS. We awoke at the uncomfortably early hour of 5:30 a.m. Our eyes were attacked by the unforgiving rays of the rising Sun
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B. The writer didn't mention anything significant .

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3 years ago
Differentiate amihan and habagat
nasty-shy [4]

Answer:

Amihan is known as the Northeast monsoon while Habagat is known as the Southwest monsoon.

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3 years ago
Sunlight strikes a piece of crown glass at an angle of incidence of 38.0°. Calculate the difference in the angle of refraction b
zhuklara [117]

Answer:

Difference in the angle of refraction = 0.3°

41.04° is the minimum angle of incidence.

Explanation:

Angle of incidence  = 38.0°

For yellow light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for yellow light which is 1.523

n₂ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.523}{1}

{sin\theta_2}=0.9377

Angle of refraction for yellow light = sin⁻¹ 0.9377 = 69.67°.

For green light :

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index for green light which is 1.526

n₂ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{38.0}^0}=\frac {1.526}{1}

{sin\theta_2}=0.9395

Angle of refraction for green light = sin⁻¹ 0.9395 = 69.97°.

The difference in the angle of refraction = 69.97° - 69.67° = 0.3°

Calculation of the critical angle for the yellow light for the total internal reflection to occur :

The formula for the critical angle is:

{sin\theta_{critical}}=\frac {n_r}{n_i}

Where,  

{\theta_{critical}} is the critical angle

n_r is the refractive index of the refractive medium.

n_i is the refractive index of the incident medium.

n₁ is the refractive index for yellow light which is 1.523 (incident medium)  

n₂ is the refractive index of air which is 1 (refractive medium)

Applying in the formula as:

{sin\theta_{critical}}=\frac {1}{1.523}

The critical angle is = sin⁻¹ 0.6566 = 41.04°

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4 years ago
Join my Kahoo t<br> pin-04454287<br><br> join if u like anime
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Answer:

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