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tatyana61 [14]
3 years ago
5

A weather balloon is Floating at a constant height above Earth when it releases a pack hot instruments. If the pack hits the gro

und with velocity of 0. -73.5 m/s , how far did the packet fall?
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

The pack has fallen 275.6 m

Explanation:

The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where, choosing upward as positive direction:

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

s is the vertical displacement

For the pack in this problem,

u = 0

v = -73.5 m/s

Solving for s, we find how far the packet has fallen:

s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m

And the negative sign means the direction of the displacement is downward.

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A particle moves on a line away from its initial position so that after t hours it is s = 6t2 + 2t miles from its initial positi
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<span>32 mph
   First, let's calculate the location of the particle at t=1, and t=4
 t=1
 s = 6*t^2 + 2*t
 s = 6*1^2 + 2*1
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 s = 8 t = 4
 s = 6*t^2 + 2*t s = 6*4^2 + 2*4
 s = 6*16 + 8
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   So the particle moved from 8 to 104 over the time period of 1 to 4 hours. And the average velocity is simply the distance moved over the time spent. So:
 avg_vel = (104-8)/(4-1) = 96/3 = 32
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6 0
3 years ago
If hydrogen and helium are the most abundant elements in the unoverse , then why are living organisms composed primarily of carb
Mumz [18]

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Most of materia isnt life.

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3 0
3 years ago
Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati
Tatiana [17]

Answer:

The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

         Let C denote the circumference

      So  

               C = 2 \pi r

      =>     r = \frac{C}{2 \pi}

               r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142}  = 6.365*10^6 m

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

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                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

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                       = \frac{(40000440-40000*10^3)}{2*3.142}

                       = 70.02m

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