Answer:
When the light ray travels from rarer to denser medium it bends towards the normal while that of rarer to denser goes away from normal.
Explanation:
A ray of light EF in air is incident on the glass surface PQ at point O. As the ray EO enters from air (rarer medium) to glass (denser medium), the ray bends towards normal and follows the path OO' inside the glass slab. At point O', refraction enters from glass (denser medium) to air (rarer medium) the ray bends away from normal and follows the path O'H outside the glass slab. Here the ray EF is called incident ray, OO' called refracted ray and O'H called emergent ray.
As per the laws of refraction, the emergent ray OlH will be parallel to the incident ray EF. The perpendicular distance O'I=x between the original path of incident ray and the emergent ray is called the lateral displacement.
Note: When the light ray has incidental in a medium and after this the light ray reflected in different media and then comes out in the same medium as it was incidence then the incident ray and emergent ray are parallel to each other.
Answer:
The angle is
Explanation:
From the question we are told that
The distance of the dartboard from the dart is
The time taken is
The horizontal component of the speed of the dart is mathematically represented as
where u is the the velocity at dart is lunched
so
substituting values
=>
From projectile kinematics the time taken by the dart can be mathematically represented as
=>
=>
