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Fynjy0 [20]
3 years ago
11

I need this type out answer question.

Physics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

<em>The ball has 7.35 joules of energy at position B.</em>

<em>The velocity of the ball at position A is 3.13 meter/second</em>

Explanation:

<u>Kinetic and Gravitational Potential Energy</u>

Kinetic energy is the form of energy that an object or a particle has by reason of its motion. An object of mass m and speed v has kinetic energy calculated by:

\displaystyle K=\frac{1}{2}m.v^2

Gravitational Potential Energy is the form of energy that an object has by reason of its height h relative to a certain reference. It can be calculated as follows:

U=m.g.h

Where g is the acceleration of gravity.

The figure shows a pendulum with a bob (ball) of mass m=1.5 Kg. When it's pulled to point B, it has a height of h= 0.5 m and set to rest.

The potential energy at that point is:

U=1.5\ Kg\cdot 9.8 \ m/s^2\cdot 0.5\ m

U=7.35\ J

The ball has 7.35 joules of energy at position B.

When the ball is released, all of the potential energy is transformed into kinetic energy when reaches point A. Thus:

K=7.35 J

From the equation of kinetic energy, we solve for v:

\displaystyle v=\sqrt{\frac{2K}{m}}

\displaystyle v=\sqrt{\frac{2\cdot 7.35}{1.5}}

\displaystyle v=\sqrt{\frac{14.7}{1.5}}

\displaystyle v=\sqrt{9.8}

v = 3.13 m/s

The velocity of the ball at position A is 3.13 meter/second

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You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
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B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

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Which of the following lists the composition of the Earth’s outer core?
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