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Fynjy0 [20]
3 years ago
11

I need this type out answer question.

Physics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

<em>The ball has 7.35 joules of energy at position B.</em>

<em>The velocity of the ball at position A is 3.13 meter/second</em>

Explanation:

<u>Kinetic and Gravitational Potential Energy</u>

Kinetic energy is the form of energy that an object or a particle has by reason of its motion. An object of mass m and speed v has kinetic energy calculated by:

\displaystyle K=\frac{1}{2}m.v^2

Gravitational Potential Energy is the form of energy that an object has by reason of its height h relative to a certain reference. It can be calculated as follows:

U=m.g.h

Where g is the acceleration of gravity.

The figure shows a pendulum with a bob (ball) of mass m=1.5 Kg. When it's pulled to point B, it has a height of h= 0.5 m and set to rest.

The potential energy at that point is:

U=1.5\ Kg\cdot 9.8 \ m/s^2\cdot 0.5\ m

U=7.35\ J

The ball has 7.35 joules of energy at position B.

When the ball is released, all of the potential energy is transformed into kinetic energy when reaches point A. Thus:

K=7.35 J

From the equation of kinetic energy, we solve for v:

\displaystyle v=\sqrt{\frac{2K}{m}}

\displaystyle v=\sqrt{\frac{2\cdot 7.35}{1.5}}

\displaystyle v=\sqrt{\frac{14.7}{1.5}}

\displaystyle v=\sqrt{9.8}

v = 3.13 m/s

The velocity of the ball at position A is 3.13 meter/second

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Answer:

<h2>59.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 70 × 0.85

We have the final answer as

<h3>59.5 N</h3>

Hope this helps you

6 0
3 years ago
If a frictional force of 4 N is acting against a push of 53 N and the box that is being pushed is 4 kg, what is its acceleration
kifflom [539]

Answer:

gggggggggggg

Explanation:

3 0
3 years ago
Two motorcyclists are riding side-by-side at night and the distance between their center-mounted headlights is 1.40 m. (a) If th
dezoksy [38]

Answer:

θ = 1.591 10⁻² rad

Explanation:

For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source

         

Let's write the diffraction equation for a slit

       a sin θ = m λ

The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ

             θ = λ / a

In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.

           θ = 1.22 λ / D

Where D is the diameter of the pupil

 Let's apply this equation to our case

        θ = 1.22 600 10⁻⁹ / 0.460 10⁻²

        θ = 1.591 10⁻² rad

This is the angle separation to solve the two light sources

6 0
3 years ago
if 6000j of energy is supplid to a machine to lift a load of 300N through a vvertical height of 1M calculatework out put​
kari74 [83]

Answer:

300J

Explanation:

Work done = Force x the distance travelled in the direction of the force

=300 x 1

=300J

8 0
3 years ago
¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
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