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Rom4ik [11]
3 years ago
11

100 POINTS.

Chemistry
2 answers:
Alchen [17]3 years ago
7 0

Answer:

H3PO4 + 3NaBr --> 3HBr + Na3PO4

Explanation:

UNO [17]3 years ago
6 0

Answer:

Double Displacement (Metathesis)

Explanation:

Double Displacement (Metathesis) is like a baking soda and vinegar rocket. Only it doesn't explode and make a mess everywhere

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Use Boyle's Law of Pressure: P1 x V1 = P2 x V2. Givens: P1=0.9 atm V1=                4 P2= 0.9 atm Find: V2 Equation: 0.9 atm x 4 x 4 L = 0.20 atm x V2Solve: 36 atmL= 0.20 atm x V2 18 : = V2 Short answer: The new volume is 104 ml. 
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Water can act as both an acid and a base in an ionization reaction to form (H) and OH ions.
matrenka [14]
Sorry I need points :)
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How many moles of oxygen would be needed to produce 84 moles of sulfur trioxide according to the following balanced chemical equ
olganol [36]

Answer:

126 moles

Explanation:

2S +3 o2=2so3

So if 2 moles of so3 required 3 moles of oxygen

. So 84 moles of so3 will require 84*3/2=126 moles of oxygen

4 0
3 years ago
Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the
jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

First measured value of density, d_1 = 1.019 g/mL

Second measured value of density, d_2 = 1.498 g/mL

Third measured value of density, d_3 = 1.572 g/mL

Putting values in above equation, we get:

\rho_{mix}=\frac{d_1+d_2+d_3}{3}

\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0
3 years ago
What happens when The vapour obtained by dropping conc. H2SO4 in a mixture of KI and MnO2 is treated with hypo solution​
Shalnov [3]

Iodine is decolorized.

The first reaction stated in the question occurs as follows;

2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)

The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.

The equation of the titration reaction is;

2Na2S2O3 + I2→ Na2S4O6 + 2NaI

When this reaction takes place, iodine is decolorized due to its reduction to I^-.

6 0
2 years ago
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