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3 years ago

100 POINTS.

Chemistry

2 answers:

Alchen [17]3 years ago

7 0

Answer:

H3PO4 + 3NaBr --> 3HBr + Na3PO4

Explanation:

UNO [17]3 years ago

6 0

Answer:

Double Displacement (Metathesis)

Explanation:

Double Displacement (Metathesis) is like a baking soda and vinegar rocket. Only it doesn't explode and make a mess everywhere

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The nucleus of an atom contains positively charged particles, called protons, and neutral particles, called neutrons. How is the

NISA [10]

Answer:

Explanation:

D. A strong force exists between the particles in a nucleus, and this force is usually stronger than the electric forces that would pull them apart.

A strong force acts only on very short distances, and stronger than electric forces when particles are very close.

3 0

4 years ago

What is the oxidation state of each element in the compound CaSO4? Include + or - in your answers as appropriate.

BartSMP [9]

Answer:- Ca = +2, S = +6 and O = -2

Solution:- There are certain rules for oxidation numbers. As per the rule, oxidation number of alkaline earth metals in their compounds is +2.

Oxidation number of oxygen in it's compounds is -2(except peroxides) and the sum of oxidation numbers of all the elements of a neutral compound is zero.

Since, Ca is +2 and O is -2, the oxidation number of S could easily be calculated for the given compound as:

Let's say the oxidation number of S in $CaSO_4$ is $x$ . Let's make the algebraic equation and solve it.

$2+x+4(-2)=0$

$2+x-8=0$

$x-6=0$

$x=+6$

Hence. the oxidation number of Ca is +2, O is -2 and S is +6.

7 0

3 years ago

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1? 6.4 × 10−4 g 6.4 × 10−3 g

eduard

Compete Question:

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1?

Passage: "16 mmol of CDP in 1 L of buffer"

Answer:

6.4 × 10-2 g

Explanation:

$Mass = Mole × Molar Mass$

we are given from the question that 16 mmol of CDP is in 1 L of buffer

this mean that we have $16 × 10^-3$ moles of CDP in 1 liter of buffer.

so the mass of CDP in one liter of buffer will be calculate as,

mass of CDP = $16 × 10^-3$ × 403g mol−1

= $64 × 10^-1$

= 6.4 g/L

But because the question

asks us about the mass of CDP in 10 mL of solution, we will go further to calculate it like this:

6.4 g/L × 10 mL

6.4 g/L × 0.01 L = $6.4 × 10^-2$

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4 years ago

Two substances, A and Z, are to be identified. Substance A can not be broken down by a chemical change. Substance Z can be broke

I am Lyosha [343]

The answer is 3). This is because elements are the simplest form of a substance, and cannot be broken down any further. Compounds on the other hand are much more complex than elements and can be broken down INTO elements. For example, Na, sodium, is an element and cannot be broken down further. H2O, water, is a compound and can be broken down into Hydrogen and Oxygen.

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3 years ago

According to kelper, which planet travels the fastest.

damaskus [11]

It’s probably Mercury I’m not sure

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3 years ago