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grigory [225]
3 years ago
8

What is the value of X?

Chemistry
2 answers:
mylen [45]3 years ago
8 0
Hi there! The answer is x = 6

Since the length of both sides is the same, we get the following equation:
5x + 10 = 40

Subtract 10 from both sides
5x = 30

Divide both sides by 5.
x = 30 \div 5 = 6

pychu [463]3 years ago
3 0
The two sides are congruent (because of the straight line through the side)

set them equal to one another

5x + 10 = 40

Isolate the x, do the opposite of PEMDAS

5x + 10 = 40

subtract 10 from both sides

5x + 10 (-10) = 40 (-10)

5x = 30

divide 5 from both sides

5x/5 = 30/5

x = 30/5

x = 6

6 is your answer for x

hope this helps
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using the equation you wrote determine how many moles of butane c4h10 are needed to react with 5.5 moles of oxygen
GaryK [48]

Answer:

0.846 moles.

Explanation:

  • This is a stichiometric problem.
  • The balanced equation of complete combustion of butane is:

C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

  • It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.

<u><em>Using cross multiplication:</em></u>

  • 1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂
  • ??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂
  • The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.
3 0
3 years ago
When 50 ml of 1.000x10^-1m pb(no3)2 solution was added to 50 ml of 1.000x10^-1m nai solution?
podryga [215]

Balanced chemical reaction: Pb(NO₃)₂ (aq) + 2NaI(aq) → 2PbI₂(s) + 2NaNO₃(aq).

V(Pb(NO₃)₂) = 50 mL ÷ 1000 mL = 0.05 L, volume of solution.

c(Pb(NO₃)₂) = 0.1 mol/L; concentration of solution.

n(Pb(NO₃)₂) = c(Pb(NO₃)₂) · V(Pb(NO₃)₂).

n(Pb(NO₃)₂) = 0.1 mol/L · 0.05 L.

n(Pb(NO₃)₂) = 0.005 mol.

n(NaI) = c(NaI) · V(NaI).

n(NaI) = 0.1 mol/L · 0.05 L.

n(NaI) = 0.005 mol; amount of substance.

From chemical reaction: n(Pb(NO₃)₂) : n(NaI) = 1 : 2.

n(Pb(NO₃)₂) = 0.005 mol ÷ 2.

n(Pb(NO₃)₂) = 0.0025 mol; number of moles Pb(NO₃)₂ used.

n(NaI) = 0.005 mol; number of moles NaI used.

The limiting reagent is Pb(NO₃)₂.

n(PbI₂) = 0.005 mol.

m(PbI₂) = n(PbI₂) · M(PbI₂).

m(PbI₂) = 0.005 mol · 461 g/mol.

m(PbI₂) = 2.305 g; the theoretical yield of PbI₂.

3 0
3 years ago
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dusya [7]

Renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

<h3>What is Renal failure?</h3>

Renal failure is a special condition where the person is unable to manage the function of the kidney organ.

The magnesium hydroxide may cause renal failure because this salt must be eliminated by the kidney and therefore it may trigger health complications.

In conclusion, renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

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