Beef and cheddar I believe!!!
Answer:
0.3 mole
Explanation:
number of moles grams
one 14+(4×1)+14+(3×16)
1 80
? 24
Therefore, 24×1÷80 = 0.3 moles of ammonium nitrate
Answer:
T2 = 94.6 C
Explanation:
Use Clausius-Clayperyon equation.
ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K
P1 = 760 mmHg
P2 = 630 mmHg
T1 = 373 K
T2 = ?
∆Hvap = 40.7 kJ/mole
R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)
Plug in and solve for T2
ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)
T2 = 367.74 K = 94.6 C
6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)= 0.67