Answer: It's not good to make a bomb out of cleaning supplies please don't do it unless your in a Meth Lab
Explanation:
Answer: If the intermolecular forces are weak, then molecules can break out of the solid or liquid more easily into the gas phase. Consider two different liquids, one polar one not, contained in two separate boxes. We would expect the molecules to more easily break away from the bulk for the non-polar case. If the molecules are held tightly together by strong intermolecular forces, few of the molecules will have enough kinetic energy to separate from each other. They will stay in the liquid phase, and the rate of evaporation will be low. ... They will escape from the liquid phase, and the rate of evaporation will be high. To make water evaporate, energy has to be added. The water molecules in the water absorb that energy individually. Due to this absorption of energy the hydrogen bonds connecting water molecules to one another will break.
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Answer:
Momentum = (mass) x (speed)
Mass is constant, so the rate of change of momentum is
(mass) x (rate of change of speed) .
But (rate of change of speed ) is just acceleration.
So the rate of change of momentum is (mass) x (acceleration).
But (mass) x (acceleration) is Force.
So Force is the rate of change of momentum. Verrrrrrrry interesting !
In this problem, Force = (40 kg) x (9 m/s²) = 360 newtons.
One 'Newton' is one kilogram-meter per second² .
Unit of momentum is (kilogram)-(meter per second), so 'newton'
is also a unit of time rate of change of momentum.
Rate of change of momentum is 360 momentum units per second.
Answer:
(c) 
(d) 
Explanation:
Hello,
In this case, the problem is:
Assume that you are designing a reformer reactor that is part of a fuel cell fuel processor system that will use natural gas (primarily methane, CH₄) as the primary fuel for a 100 kWe fuel cell.
Thus, the undergoing chemical reactions are:
Hence, assuming a 60% overall efficiency for the fuel cell and considering that methane's heat of combustion is 50000 kJ/kg, the flow rate methane turns out:
Now, one could compute the desired steam flow-rate by assuming a steam to carbon ratio of 2.5 to avoid coking:
Finally, to compute the desired air flow-rate, it is necessary to specify a O₂ to CH₄ ratio of 0.5 (based on the first reaction):
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