Answer:
Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.
Explanation:
For example:
If you created 0.5 moles of Aluminium Oxide the molecular weight of Aluminium Oxide is 101.96g/mole, so you would get 50.98g as the theoretical yield.
So multiply,..
101.96x0.5= 50.98
This is the correct way to calculate the theoretical yield
......
Answer:
IUPAC Rules for Alkane Nomenclature
Find and name the longest continuous carbon chain.
Identify and name groups attached to this chain.
Number the chain consecutively, starting at the end nearest a substituent group.
Designate the location of each substituent group by an appropriate number and name.
Explanation:
Answer:
Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.
Explanation:
Percentage of element in compound :
![=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctext%7Bnumber%20of%20atoms%7D%5Ctimes%20text%7BAtomic%20mass%7D%7D%7B%5Ctext%7Bmolar%20mas%20of%20compound%7D%7D%5Ctimes%20100)
(a) Urea, ![(NH_2)_2CO](https://tex.z-dn.net/?f=%28NH_2%29_2CO)
Molar mass of urea = 60 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 2
![N\%=\frac{2\times 14 g/mol}{60 g/mol}\times 100=46.67\%](https://tex.z-dn.net/?f=N%5C%25%3D%5Cfrac%7B2%5Ctimes%2014%20g%2Fmol%7D%7B60%20g%2Fmol%7D%5Ctimes%20100%3D46.67%5C%25)
(b) Ammonium nitrate, ![NH_4NO_3](https://tex.z-dn.net/?f=NH_4NO_3)
Molar mass of ammonium nitrate = 80 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 2
![N\%=\frac{2\times 14 g/mol}{80 g/mol}\times 100=35.00\%](https://tex.z-dn.net/?f=N%5C%25%3D%5Cfrac%7B2%5Ctimes%2014%20g%2Fmol%7D%7B80%20g%2Fmol%7D%5Ctimes%20100%3D35.00%5C%25)
(c) Nitric oxide, NO
Molar mass of nitric oxide = 30 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 1
![N\%=\frac{1\times 14 g/mol}{30 g/mol}\times 100=46.67\%](https://tex.z-dn.net/?f=N%5C%25%3D%5Cfrac%7B1%5Ctimes%2014%20g%2Fmol%7D%7B30%20g%2Fmol%7D%5Ctimes%20100%3D46.67%5C%25)
(d) Ammonia, ![NH_3](https://tex.z-dn.net/?f=NH_3)
Molar mass of ammona = 17 g/mol
Atomic mass of nitrogen = 14 g/mol
Number of nitrogen atoms = 1
Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.
Answer:
The purpose of a lab report is to organize and communicate what you did in your experiment.
Explanation: