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balandron [24]
3 years ago
11

hannah says that 1/8 is not on the number line and cannot be plotted. write a note to hannah about her misunderstanding

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer and explanation :

Hannah said that \frac{1}{8} is not on the number line but she is wrong because \frac{1}{8} can be represented on the number line

When we convert the fraction \frac{1}{8} into decimal then it is equal to 0.125

And 0.125 lies between 0 and 1

If we divide one unit on number line into 10 parts then 0.125 lie between 0.1 and 0.2

And we know that any real number can be represented on number line as 0.125 is a real number so it can be represented on the number line

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HELP ME PLEASE 10 POINTS ON IT PLEASE HELP ME ​
Svetach [21]

Answer:

4, 12, 16 (respectively)

Step-by-step explanation:

if you need one just comment and ill add one

5 0
3 years ago
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The base of a solid in the region bounded by the two parabolas y2 = 8x and x2 = 8y. Cross sections of the solid perpendicular to
Usimov [2.4K]

The two curves intersect at two points, (0, 0) and (8, 8):

x^2=8y\implies y=\dfrac{x^2}8

y^2=\dfrac{x^4}{64}=8x\implies\dfrac{x^4}{64}-8x=0\implies\dfrac{x(x-8)(x^2+8x+64)}{64}=0

\implies x=0,x=8\implies y=0,y=8

The area of a semicircle with diameter d is \dfrac{\pi d^2}8. The diameter of each cross-section is determined by the vertical distance between the two curves for any given value of x between 0 and 8. Over this interval, y^2=8x\implies y=\sqrt{8x} and \sqrt{8x}>\dfrac{x^2}8, so the volume of this solid is given by the integral

\displaystyle\frac\pi8\int_0^8\left(\sqrt{8x}-\dfrac{x^2}8\right)^2\,\mathrm dx=\frac{288\pi}{35}

6 0
3 years ago
HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!
rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

3 0
3 years ago
This is math, help me with it plz
dangina [55]
Answer: X=136 degrees
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3 years ago
Lainey bought a set of 20 markers for $6 dollar sign, 6. What is the cost of 1 marker?
marin [14]
Hello!

To find the price of one marker you divide the price paid by the amount of markers bought

6 / 20 = 0.30

A marker cost $0.30

The answer is $0.30

Hope this helps!
5 0
3 years ago
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