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3 years ago

A 0.10-kilogram ball dropped vertically from a

Physics

1 answer:

7nadin3 [17]3 years ago

8 0

Answer:

Explanation:

P.E = mass × acceleration due to gravity × height

initial P.E = 0.10 × 9.81 × 10 ( in question 100 m is a typing error , it must be 1 .00 m )

= 0.981J

final P.E = 0.10 × 9. 81 × 0.80

= 0.7848 J

HENCE mechanical energy lost = 0. 981 - 0.7848

= 0.1962 J

= 0.20 J

HENCE B

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When gravitational forces and air resistance equalize on an object that is falling toward earth and the object stops acceleratin

abruzzese [7]

<span>when the gravitational forces and air resistance equalize on an object that is falling toward the earth and the object stops accelerating its called TERMINAL VELOCITY</span>

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3 years ago

Which of the following has the largest inertia?

Shkiper50 [21]

Option D, a semi truck parked in a parking lot

Reason: Inertia is the state of a body which needs a force to come into the act of motion.

The more massive the object is the more is its inertia.

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4 years ago

What is time taken by the stone ?

SSSSS [86.1K]

The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

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8 0

2 years ago

A 65 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 5 m/s. how fast is he going as he l

KIM [24]

m = mass of trampoline artist = 65 kg

v₀ = initial speed of the artist at the top of platform = 5 $\frac{m }{s}$

h = height through which the artist drop before landing on trampoline = 3 m

v = final speed of the artist just before landing on trampoline = ?

using conservation of energy

Kinetic energy of artist just before landing = initial kinetic energy at the top of platform + potential energy at the top of platform

(0.5) m v² = (0.5) m v₀² + mgh

dividing each term by "m"

(0.5) v² = (0.5) v₀² + gh

inserting the values

(0.5) v² = (0.5) (5)² + (9.8)(3)

v = 9.2 $\frac{m }{s}$

x = compression of the trampoline = ?

k = spring stiffness constant = 62000 $\frac{N }{m}$

Assuming the lowest depression point as reference line for measuring the potential energy

using conservation of energy

kinetic energy of artist + potential energy of artist before landing = spring potential energy of trampoline

(0.5) m v² + mg x = (0.5) k x²

inserting the values

(0.5) (65) (9.2)² + (65 x 9.8) x = (0.5) (62000) x²

x = 0.31 m

6 0

3 years ago

Pressure and volume changes at a constant temperature can be calculated using

V125BC [204]

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.

The basic mathematical representation of this phenomenon is as follows -

$P \alpha \frac{1}{V}$

$P = \frac{k}{V} \\PV = k$

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

3 0

3 years ago