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4 years ago

According to Kepler, what do all bodies in orbit around another have in common?

1 answer:

3 0

D.
All follow an elliptical path that has two foci, rather than a circular path.

Kepler found paths are elliptical, not circular

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How do ultraviolet rays affect skin

yan [13]

Ultraviolet rays from the sun are very strong, therefore if direct contact is made with skin, it could cause sun burn, or in a worser case skin cancer

4 0

4 years ago

Why is it that an object can accelerate while

posledela

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

3 0

3 years ago

Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs

mafiozo [28]

Answer:

Magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

Explanation:

Magnitude of first vector = $|A| = 13\ \text{units}$

Angle = $\theta_1=27^{\circ}$

Magnitude of second vector = $|B| = 11\ \text{units}$

Angle = $\theta_2=45^{\circ}$

x component of first vector

$A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}$

y component of first vector

$A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}$

x component of second vector

$B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}$

y component of first vector

$B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}$

Adding the magnitudes

$C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}$

$C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}$

Magnitude of the sum of the vectors would be

$|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}$

The direction would be

$\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}$

The magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

4 0

3 years ago

Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of 9q. Sphere B carries a charge of -q. Sphere C

Leona [35]

Answer:

Explanation:

A and B are touched .

charge on each of them after touching = (9q - q) / 2 = 4q

when C is touched with A

charge on A and C each after touching

= 4q + 0 / 2 = 2q

When C is touched with B

charge on each of them

(2q + 4q ) / 2 = 3 q

Final charge on C = 3q

6 0

4 years ago

Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of

frez [133]

Answer:

Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.

Explanation:

Describe how the shape of the coast may influence an incoming wave. Explain using key terms such as reflection off the shape of the coast and reflection of incoming waves.

6 0

3 years ago