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olga55 [171]
3 years ago
7

Convert 3.2 ft^2 to square inches

Chemistry
1 answer:
tangare [24]3 years ago
6 0

460.8 square inches

3.2 * 144 = 460.8

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The particle size of solute particles does not affects the rate. Question 14 options: True False
stepan [7]
The answer is false
8 0
3 years ago
The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
3 years ago
If a 45 mM phosphate solution(solution A) had an absorbance of 1.012. What would be the absorbance if 11 mL of solution A was us
timofeeve [1]

Answer:

0.550

Explanation:

The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.

A = ε . <em>l</em> . c

where,

ε: absorptivity of the species

<em>l</em>: optical path length

A 45 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . <em>l</em> . c

1.012 = ε . <em>l</em> . 45 mM

ε . <em>l</em>  = 0.022 mM⁻¹

We can find the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

45mM . 11mL = C₂ . 20.0 mL

C₂ = 25 mM

The absorbance of the second solution is:

A = (ε . <em>l</em> ). c

A = (0.022 mM⁻¹) . 25 mM = 0.55 (rounding off to 3 significant figures = 0.550)

8 0
3 years ago
I will give braniliest
kap26 [50]
B. Holocaust
your welcome
3 0
3 years ago
Read 2 more answers
Find the mass in grams of 1.55 x 1023 molecules of Cl2?
forsale [732]
We are told that there are 1.55 x 10²³ molecules of Cl₂ and we need to calculate the mass of these molecules. We need to do several conversions. The easiest will be to convert the amount of molecules to the number of moles present. To do this, we need to use Avogadro's number which is 6.022 x 10²³ molecules/mole.

1.55 x 10²³ molecules / 6.022 x 10²³ molecules/mole = 0.257 moles Cl₂

Now that we have the moles of Cl₂ present, we can convert this value to a mass of Cl₂ by using the molecular mass of Cl₂. The molecular mass is 70.906 g/mol.

0.257 moles Cl₂ x 70.906 g/mol = 18.3 g Cl₂

Therefore, 1.55 x 10²³ molecules of Cl₂ will have a mass of 18.3 g.
7 0
3 years ago
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