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Papessa [141]
3 years ago
10

Reasons why construct is a great beginner game engine

Computers and Technology
1 answer:
Vlada [557]3 years ago
8 0

Answer:

Construct 2 is a very intuitive drag and drop for creating 2D games. The learning curve is super fast, and the interface looks a lot like Microsoft products, so it makes it an ideal tool for PC users who have never looked at a game engine before

Explanation:

You might be interested in
which classification of money describes money that can be accessed quickly and easily, and includes coins and paper money as wel
zhenek [66]

Money that can be promptly and easily appraised falls under the M1 Money classification.

<h3>What are broad and narrow money, respectively?</h3>

Broad money typically refers to M2, M3, and/or M4. The most liquid kinds of money, such as currency (banknotes and coins), as well as bank account balances that may be instantly changed into currency or used for cashless transactions, are generally referred to as "narrow money" (overnight deposits, checking accounts).

<h3>Describe Narrow Money.</h3>

All of the actual money that the central bank has falls under the category of "narrow money," which is a subset of the money supply. Demand deposits, money, and other liquid assets are included. In the US, "narrow money" is referred to as M1 (M0 plus demand accounts).

To know more about Money classification visit:-

brainly.com/question/28095328

#SPJ1

5 0
1 year ago
X = 9 % 2if (x == 1):  print ("ONE")else:  print ("TWO")
IgorC [24]

Answer:

ONE

Explanation:

It prints one because % is modulus, which is remainder division. It divides the numbers provided and returns the remainder of the division. 9 / 2 = 4 with 1 remainder, which leads us to our answer.

4 0
1 year ago
Digital cameras are less susceptible to UV light.Select one of the options below as your answer:A. TrueB. False
horrorfan [7]
<span>Digital cameras are less susceptible to UV light. TRUE. In fact, there is an existing photography called Ultraviolet Photography. It is a process of photography that records images by using the light from the ultraviolet spectrum. There are two possible ways to use UV in taking photographs: via reflected UV and UV induced fluorescence.</span>
4 0
3 years ago
Read 2 more answers
Top/Bottom Rules allow a user to apply conditional formatting to cells that fall within the top or bottom numbers or percentile.
vfiekz [6]

The numbers of  items that the user can include in the rule is the top or bottom 100 items only.

<h3>What is Top/Bottom Rules?</h3>

Top/Bottom Rules is known to be a rule where there is a premade form of conditional formatting which is often used in Excel to alter the set up  of cells in a range.

Note that the Top/Bottom Rules will allow a user to make changes to the top or bottom 100 items only as it only pertains to things that are up and those that are at the bottom.

Learn more about Top/Bottom Rules from

brainly.com/question/1862654

7 0
1 year ago
In the simulation, player 2 will always play according to the same strategy. The number of coins player 2 spends is based on wha
baherus [9]

The simulation, player 2 will always play according to the same strategy.

Method getPlayer2Move below is completed by assigning the correct value to result to be returned.

Explanation:

  • You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.

#include <bits/stdc++.h>  

using namespace std;

bool getplayer2move(int x, int y, int n)  

{

   int dp[n + 1];  

   dp[0] = false;  

   dp[1] = true;  

   for (int i = 2; i <= n; i++) {  

       if (i - 1 >= 0 and !dp[i - 1])  

           dp[i] = true;  

       else if (i - x >= 0 and !dp[i - x])  

           dp[i] = true;  

       else if (i - y >= 0 and !dp[i - y])  

           dp[i] = true;  

       else

           dp[i] = false;  

   }  

   return dp[n];  

}  

int main()  

{  

   int x = 3, y = 4, n = 5;  

   if (findWinner(x, y, n))  

       cout << 'A';  

   else

       cout << 'B';  

   return 0;  

}

8 0
3 years ago
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