Answer:
<h2>864π in³</h2>
Step-by-step explanation:
Volume of the water is equivalent to the volume of a cylinder = πr²h where;
r is the radius of the cylindrical tank
h is the height of the water
Given parameters
radius of the cylindrical tank r = 1feet = 12 inches
height of the water inside the tank = 6inches
Volume of the water = πr²h
Volume of the water = π(12)²*6
Volume of the water = π*144*6
Volume of the water = 864π in³
<em></em>
<em>Hence the volume of the water is 864π in³</em>
8 s -11 s + 6= - 3 s + 6=
= 3( - s +2)
(6-8)/(1+2)= -2/3 the answer to the question
As I've shown on picture that I attached:
∠ADC=∠ADB+∠BDC⇒134=5x+4+7x-2
12x+2=134
12x=132⇒x=132/12
x=11
Angle BDC measure 7x-2=7*11-2⇒∠BDC=75.