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4 years ago

With what velocity does it hit the ground?

Physics

1 answer:

Serggg [28]4 years ago

8 0

That depends on a number of things that we don't know because you haven't told us.

If any of the things on this list changes, then the answer to the question changes:

-- What is "it" ?

-- Was it dropped, thrown, fired, or launched ?

-- From what height above the ground ?

-- With what speed ?

-- In what direction ?

-- What is the acceleration of gravity where this took place ?

-- Did any drag act on it, due to liquid or gas, before it hit the ground ?

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Mae prefers to complete graphs or charts to show the information she has learned. What kind of learner is Mae likely to be?

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Answer:

Prob. D

Explanation:

I am also a Visual Learner.

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3 years ago

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A shovel pushes on dirt and the dirt pushes back on the shovel. The dirt pushing back is

Leno4ka [110]

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3 years ago

Which two questions can be used to identify criteria for how successful the design of an efficient high altitude drone is?

AfilCa [17]

Answer:

Explanation:

Remark

Though you do not know what height the previous drone reached, I would think reading 8000 m would be quite an accomplishment. Answer 1: A

B: I wouldn't pick B. Increased cost isn't going to contribute to design success.

C. If the efficiency is low to start with, increasing it some won't matter. On the other hand if the efficiency is moderate or good increasing it by 35% is a good thing. Let's hold on to this answer.

D: It has to work at low altitudes in order to work at high altitudes. I wouldn't pick D

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2 years ago

Page worth 100 points please help

laila [671]

Answer:

a) the total circle of "initial" is Epot./Eel. and the total circle of "final" is Ekin.

b)intia: 0.5 * 50 * 4^2 = 400 J

final: 0 J = 0.5 * 50 * 0^2

Explanation:

c) in the initial phase the spring is compressed and so has Epot but then the Energie changes to be totally Ekin (in final phase) and so the Epot becomes 0

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4 years ago

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A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en

Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

$-\frac{dU}{dx}=F\\ dU=-Fdx$

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

$U=\frac{-7}{2}x^{2} + 11x + c$

we know that U is equal to 26 J when x is zero, so:

$U=\frac{-7}{2}x^{2} + 11x + c$

$26=\frac{-7}{2}(0)^{2} + 11(0) + c$

$26=c$

Finally, the equation for the potential energy is:

$U(x)=\frac{-7}{2}x^{2} + 11x + 26$

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

$x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}$