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asambeis [7]
3 years ago
6

An engine has an energy input of 125j and 35 j of that energy is transformed into useful energy

Physics
1 answer:
Tatiana [17]3 years ago
5 0
The engine's efficiency is (35J)/125J) = 28% .

Do you have a different question to ask ?
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The principal of uniformitarian states that
Akimi4 [234]
It started that the present is the key to the past. The process that we see in operation today are the same ones that have operated in the geologic past.
4 0
3 years ago
A child with a mass of 23 kg rides a bike with a mass of 5.5 kg at a velocity of 4.5 m/s to the south. Compare the momentum of t
serg [7]

Answer:

Explanation:

Given the following data;

Mass of child = 23 kg

Mass of bike = 5.5 kg

Velocity = 4.5 m/s

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

To find the momentum of each of them;

I. Momentum of the child

Momentum C = mass * velocity

Momentum C = 23 * 4.5

Momentum C = 103.5 Kgm/s

II. Momentum of the bike

Momentum B = mass * velocity

Momentum B = 5.5 * 4.5

Momentum B = 24.75 Kgm/s

Hence, we can deduce from the calculations that the momentum of the child is greater than that of the bike because of the higher mass possessed by the child.

4 0
3 years ago
I WILL MARK BRAINLIEST IF CORRECT!!!
julsineya [31]

0.05*0.2=0.05*0.15+0.015*m2',

m2'=1/6 m/s,

m2'=0.17 m/s

N I C E - D A Y!

6 0
3 years ago
The element chlorine is found in nature as a molecule that can be represented as - A. Cl.
poizon [28]
A
Cl is the chemical symbol for chlorine numbers after it are isotopes
5 0
3 years ago
A motorcycle is speeding along at a velocity of120kph.Then, it changes to a velocity of 150 kph for 2 minutes.What is the motorc
Taya2010 [7]

Answer:

Explanation:

a=v-u/t

a=acceleration

v=final velocity

u=initial velocity

t=tme taken

we need to convert from kph to ms⁻¹

v= 150*1000/60*60= 41.67ms⁻¹

u= 120*1000/60*60= 33.33ms⁻¹

t= 2*60= 120s

a=41.67-33.33/120

a=8.34/120

a=0.0694ms⁻²

8 0
3 years ago
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