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kotykmax [81]
3 years ago
14

An experimentalist fires a beam of electrons, creating a visible path in the air that can be measured. The beam is fired along a

direction parallel to a current-carrying wire, and the electrons travel in a circular path in response to the wire's magnetic field. Assuming the mass and charge of the electrons is known, what quantities would you need to measure in order to deduce the current in the wire and the magnetic field due to that current?
Physics
1 answer:
gtnhenbr [62]3 years ago
4 0

Answer:  

Velocity of the electron in the beam.

Radius of the circulating electrons due to the magnetic field.

Explanation:

We have a Mathematical expression for the force on a moving charge in a magnetic field as:

F=q.v.B.sin \theta ...........................(1)

where:

q= charge on the particle in coulomb

v= velocity of the charge projected into the magnetic field

B= intensity of the magnetic field in tesla

\theta= angle between the velocity and direction of magnetic field

For the forces on rotating mass we have the formula:

F=m.\frac{v^2}{r}..........................................(2)

where:

m= mass of the charged particle

v= velocity of projection of charge into the magnetic field

r= radius of the path traced  by the charge in the magnetic field

From eq. (1) and (2) we can calculate the magnetic field .

Now,

Using Ampere's Law we have:

B = \frac{\mu_0 .I}{2 \pi r}

where:

I= current in the wire

\mu_0= The permeability of free space.

r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)

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1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

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∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

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2 years ago
Question 9:<br> All parts thank you !
WINSTONCH [101]
Photo Math is the answer
5 0
3 years ago
It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd tim
GaryK [48]

Answer:

3.1 m/s

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3 years ago
A series circuit has two 10-ohm bulb is added in a series. Technician A says that the three bulbs will be dimmer than when only
ANTONII [103]

Answer:

Technician  A  is right. The situation will happens even with only two bulbs in series

Explanation:

We must take into account that

1.- All electric device need its nominal voltage to operate

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3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).

4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split  between the two bulbs ( we  could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.

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sattari [20]

Answer:

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v² = 2 g h

v=\sqrt{2gh}\ m/s

6 0
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