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kotykmax [81]
3 years ago
14

An experimentalist fires a beam of electrons, creating a visible path in the air that can be measured. The beam is fired along a

direction parallel to a current-carrying wire, and the electrons travel in a circular path in response to the wire's magnetic field. Assuming the mass and charge of the electrons is known, what quantities would you need to measure in order to deduce the current in the wire and the magnetic field due to that current?
Physics
1 answer:
gtnhenbr [62]3 years ago
4 0

Answer:  

Velocity of the electron in the beam.

Radius of the circulating electrons due to the magnetic field.

Explanation:

We have a Mathematical expression for the force on a moving charge in a magnetic field as:

F=q.v.B.sin \theta ...........................(1)

where:

q= charge on the particle in coulomb

v= velocity of the charge projected into the magnetic field

B= intensity of the magnetic field in tesla

\theta= angle between the velocity and direction of magnetic field

For the forces on rotating mass we have the formula:

F=m.\frac{v^2}{r}..........................................(2)

where:

m= mass of the charged particle

v= velocity of projection of charge into the magnetic field

r= radius of the path traced  by the charge in the magnetic field

From eq. (1) and (2) we can calculate the magnetic field .

Now,

Using Ampere's Law we have:

B = \frac{\mu_0 .I}{2 \pi r}

where:

I= current in the wire

\mu_0= The permeability of free space.

r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)

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When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin
dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) 1.21\times 10^{15}Hz

Explanation:

We have given Wavelength of the light  \lambda = 240 nm

According to plank's rule ,energy of light

E = h\nu = \frac{hc}{}\lambda

E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

E = KE_{max}+\Phi _{0}, here \Phi _0 is work function.

\Phi _{0}=E - KE_{max}= 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}

\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }

\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm

Part (C) In this part we have to find the cutoff frequency

\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz

5 0
3 years ago
Some one help my science homework is due tomorrow and I'm so stuck with question 8-9, and 11-12
yuradex [85]
Off the top of my head, I only know 9 and 11, so I'll answer those two.

9) A heterotroph is an organism that relies on other organisms for food/energy
    An autotroph can produce its own food from inorganic compounds (light)

11) Vascular plants have specialized tubes for transporting nutrients
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5 0
3 years ago
A proton moving in the positive x direction with a speed of 9.9 105 m/s experiences zero magnetic force. When it moves in the po
Alex

Answer:

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

Explanation:

In order to calculate the magnitude and direction of the magnetic field, you take into account the following equation for the magnetic force on the proton:

\vec{F_B}=q\vec{v}\ X\ \vec{B}       (1)

v: speed of the proton = 9.9*10^5 m/s

q: charge of the proton = 1.6*10^-19C

B: magnetic field = ?

FB: magnetic force on the proton = 1.6*10^-13N

When the proton travels in the positive y direction (^j), you have that the proton experiences a force in the positive z direction (+^k). To obtain this direction of the magnetic force on the proton, it is necessary that the magnetic field points in the negative x direction, in fact, you have:

^j X (-^i) = -(-^k)=^k

To obtain the magnitude of the magnetic field you use:

F_B=qvBsin90\°=qvB\\\\B=\frac{F_B}{qv}=\frac{1.6*10^{-13}N}{(1.6*10^{-19}C)(9.9*10^5m/s)}\\\\B=1.01T

The magnitude of the magnetic field is 1.01T and its direction is in the negative x direction

8 0
3 years ago
It is a state of matter wherein particles are tightly packed, but are far enough apart to slide over one another.
NISA [10]

Particles that are closely packed but spaced apart enough to move over one another are called plasma. Option C is correct.

<h3>What is the plasma state of matter?</h3>

Plasma is a state of matter wherein particles are tightly packed but are far enough apart to slide over one another.

The following conditions are followed by the plasma state.

Hence, option C is correct.

To learn more about the plasma state refer;

brainly.com/question/5496865

#SPJ1

3 0
2 years ago
1. An atom that loses electrons has a ________________________ charge and an atom that gains
JulsSmile [24]
I’ll start you off

1. Positive, negative, ions

Answer a few yourself and I’ll come back and help some more.
3 0
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