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3 years ago

How far will a freely falling object fall from rest in five seconds? six seconds?

1 answer:

4 0

Distance = 1/2*gravity*velocity^2
So plugging: 1/2 * 9.8 * 25 = 122.5units
and is six second
Distance = 1/2*gravity*velocity^2
So plugging: 1/2 * 9.8 * 36= 176.4 units

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A stealth bomber is flying straight and level at a constant speed of 150 m/s at an altitude of 3500 m above the ground. It drops

dangina [55]

$Height = \frac{1}{2} gt^2 \\ \\ 3500 = \frac{1}{2} (9.8)(t^2)\\ \\3500 = 4.9t^2\\\\t^2 =714.285714286\\\\\boxed {t=26.73~seconds}$

$\sf Horizontal ~distance = velocity \times time\\\\ Horizontal distance =150 \times 26.73 \\\\Horizontal ~distance =4009.5$

5 0

3 years ago

Which of these will have the same units if acceleration is multiplied by time? Force Time velocity Pressure

Leno4ka [110]

Answer:

Velocity

Explanation:

Velocity equals the original velocity... Plus

the acceleration is multiplied by time.

8 0

3 years ago

Read 2 more answers

Answer all of them an you will get the brain list

Vlad [161]

Answer:

4. Force = 178.6 Newton.

5. Acceleration = 2.28 m/s².

6. Force = 178.6 Newton.

Explanation:

4. Given the following data;

Acceleration = 3.8 m/s²

Mass = 47kg

Force = mass * acceleration

Force = 47 * 3.8

Force = 178.6 Newton. 

5. Given the following data;

Force = 785N

Mass = 345kg

Acceleration = force/mass

Acceleration = 785/345

Acceleration = 2.28 m/s²

6. Given the following data;

Acceleration = 6m/s²

Force = 32N

Mass =force/acceleration

Mass = 32/6

Mass = 5.33 kilograms

5 0

3 years ago

A single circular current loop 14.0 cm in diameter carries a 2.40 A current. You may want to review . For related problemsolving

7nadin3 [17]

Answer:

Magnetic field at the center will be $215.314\times 10^{-7}T$

Explanation:

We have given that diameter of the loop d = 14 cm = 0.14 m

So radius $R=\frac{d}{2}=\frac{0.14}{2}=0.07m$

Current in the loop i = 2.40

We know that magnetic field at center of circular loop is given by

$B=\frac{\mu _0i}{2R}$

So $B=\frac{4\pi \times 10^{-7}\times 2.4}{2\times 0.07}=215.314\times 10^{-7}T$

Magnetic field at the center will be $215.314\times 10^{-7}T$

8 0

3 years ago

When the steel ball drops on the constant velocity cart, it follows a ____ path in the frame of reference fixed to the ____, but

Effectus [21]

Answer:

PARABOLIC, EARTH, VERTICAL, INERTIAL ang PHYSICAL LAWS

Explanation:

In this exercise you are asked to complete the missing words.

When the steel ball falls on the constant speed car, it follows a PARABOLIC path in the reference frame fixed to EARTH, but a VERTICAL straight line in the reference frame of the constant speed car. Without a fixed frame of reference, you cannot tell whether or not you are in an INERTIAL frame of reference. All frames of reference that move at constant speed relative to each other are PHYSICAL LAWS__equivilent__.

\ r

8 0

3 years ago