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attashe74 [19]
3 years ago
7

0.45 written as a common fraction in its simpliest form is​

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

45/100 = 9/20

Step-by-step explanation:

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Percent Increase in labour productivity will be equal to the percent increase in the number of articles.

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A cylindrical container of height 28cm and diameter 18cm is filled with water.The water is then poured into another container wi
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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

MEDIUM

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

4 0
3 years ago
Read 2 more answers
Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes a
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Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes already. How many more boxes must they sell to raise 180 dollars?

Answer: We are given:

The amount of money Tony's club get for every box they sell =1 \frac{1}{8} =1.125 dollar

They amount of money Tony's club has raised by selling 75 boxes is:

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The remaining need to be raised is :

180-84.375=95.625 dollars

Therefore, the number of more boxes to be sold are:

\frac{95.625}{1.125}=85

Hence, 85 more boxes they must sell to raise 180 dollars

8 0
2 years ago
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